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Question
Math
Posted 5 months ago

The square pyramid shown below has a base with sides of 10 units. The slant height of the pyramid is 8 units.

What is the vertical height, hh ?
Round your answer to the nearest tenth.
The height is \square units.
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Answer from Sia
Posted 5 months ago
Solution by Steps
step 1
Given the right triangle within the pyramid, we use the Pythagorean theorem a2+b2=c2a^2 + b^2 = c^2, where aa and bb are the legs and cc is the hypotenuse
step 2
We know the length of one leg a=5a = 5 units (half the base of the pyramid) and the hypotenuse c=8c = 8 units (the slant height of the pyramid)
step 3
We need to find the length of the other leg hh, which represents the vertical height of the pyramid
step 4
Substitute the known values into the Pythagorean theorem: 52+h2=825^2 + h^2 = 8^2
step 5
Solve for h2h^2: h2=8252h^2 = 8^2 - 5^2
step 6
Calculate h2h^2: h2=6425h^2 = 64 - 25
step 7
Simplify h2h^2: h2=39h^2 = 39
step 8
Take the square root of both sides to find hh: h=39h = \sqrt{39}
step 9
Calculate hh: h6.2h \approx 6.2 units when rounded to the nearest tenth
Answer
The height is 6.26.2 units.
Key Concept
Pythagorean Theorem
Explanation
The vertical height of the pyramid is found by using the Pythagorean theorem on the right triangle formed by the height, half the base, and the slant height of the pyramid.

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