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Question
Math
Posted 7 months ago

Use the given conditions to write an equation for the line in slope-intercept form.
Passing through (5,3)(-5,3) and parallel to the line whose equation is y=3/2x+9/4y=3 / 2 x+9 / 4
Write an equation for the line in slope-intercept form.
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Answer from Sia
Posted 7 months ago
Solution by Steps
step 1
Identify the slope of the given line. The given line is y=32x+94y = \frac{3}{2}x + \frac{9}{4}. The slope (m) is 32\frac{3}{2}
step 2
Since the new line is parallel to the given line, it will have the same slope. Therefore, the slope of the new line is also 32\frac{3}{2}
step 3
Use the point-slope form of the equation of a line, which is yy1=m(xx1)y - y_1 = m(x - x_1), where (x1,y1)(x_1, y_1) is the point the line passes through. Here, (x1,y1)=(5,3)(x_1, y_1) = (-5, 3) and m=32m = \frac{3}{2}
step 4
Substitute the values into the point-slope form: y3=32(x(5))y - 3 = \frac{3}{2}(x - (-5))
step 5
Simplify the equation: y3=32(x+5)y - 3 = \frac{3}{2}(x + 5)
step 6
Distribute the slope: y3=32x+152y - 3 = \frac{3}{2}x + \frac{15}{2}
step 7
Add 3 to both sides to solve for yy: y=32x+152+3y = \frac{3}{2}x + \frac{15}{2} + 3
step 8
Convert 3 to a fraction with a common denominator: 3=623 = \frac{6}{2}
step 9
Combine the fractions: y=32x+152+62=32x+212y = \frac{3}{2}x + \frac{15}{2} + \frac{6}{2} = \frac{3}{2}x + \frac{21}{2}
Answer
The equation of the line in slope-intercept form is y=32x+212y = \frac{3}{2}x + \frac{21}{2}.
Key Concept
Parallel lines have the same slope.
Explanation
To find the equation of a line parallel to a given line, use the same slope and apply the point-slope form with the given point.

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