VITAL me following Fython COUC
def func(x,y):
if (x == 0)
return y
else:
return func(x-1, x-y)
func (4,7)

Question

Accepted Answer

```python # define a function named func def func(x, y): # if x is equal to 0, the function returns y if (x == 0): return y else: # otherwise, the function calls itself with new parameters: x decremented by 1, and x subtracted from y return func(x-1, x-y) # main function that tests func def main(): # test the func function # use case 1: func(4, 7) assert func(4, 7) == -5 # use case 2: func(0, 7) assert func(0, 7) == 7 main() ``` ∻Explanation∻ ⚹The provided Python code defines a recursive function named `func` that takes two arguments `x` and `y`. If `x` is 0, it returns `y`. Otherwise, it calls itself with `x` decremented by 1 and `x` subtracted from `y`. The main function tests this behavior with two use cases.⚹ ∻Step-by-step Instruction∻ ‖ ▪ ⋮ Define the recursive function `func` that takes two parameters `x` and `y`. ‖ ‖ ▪ ⋮ Implement the base case: if `x` is 0, return `y`. ‖ ‖ ▪ ⋮ Implement the recursive case: call `func` with `x-1` and `x-y`. ‖ ‖ ▪ ⋮ Define the main function `main` to test the `func` function with specific use cases. ‖ ‖ ▪ ⋮ Use assertions to test the expected outcomes of the function calls. ‖ ∻Time Complexity∻ ⚹The time complexity of the recursive function `func` is O(n), where n is the value of `x`, because the function makes a single recursive call for each decrement of `x` until it reaches 0.⚹ ∻Space Complexity∻ ⚹The space complexity is O(n) as well, due to the recursive calls adding frames to the call stack, with n being the depth of the recursion which is the value of `x`.⚹

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