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Math
Posted 4 months ago

Vlad is playing on a swing set.
His horizontal distance D(t)D(t) (in m\mathrm{m} ) from the center (where being behind the center means a negative distance) as a function of time tt (in seconds) can be modeled by a sinusoidal expression of the form acos(bt)+da \cdot \cos (b \cdot t)+d.

At t=0t=0, when he pushes off, he is 1 m1 \mathrm{~m} behind the center, which is as far back as he goes. The swing reaches the center π6\frac{\pi}{6} seconds later.

Find D(t)D(t).
tt should be in radians.
D(t)=
D(t)=

\square
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Answer from Sia
Posted 4 months ago
Solution by Steps
step 1
To find the function D(t)D(t), we need to determine the values of aa, bb, and dd in the sinusoidal function acos(bt)+da \cdot \cos(b \cdot t) + d
step 2
Given that at t=0t = 0, Vlad is 1 meter behind the center, we can determine dd because this is the farthest point back he goes, which is the amplitude of the cosine function. Thus, d=1d = -1
step 3
Since the swing reaches the center π6\frac{\pi}{6} seconds later, we can find bb by using the fact that the cosine function completes a half-cycle when the swing goes from the farthest point back to the center. Therefore, bπ6=π2b \cdot \frac{\pi}{6} = \frac{\pi}{2}, which gives us b=3b = 3
step 4
The amplitude aa is the maximum distance from the center, which is also 1 meter in this case, but since we already accounted for the negative sign in dd, we have a=1a = 1
step 5
Combining the values of aa, bb, and dd, we get the function D(t)=1cos(3t)1D(t) = 1 \cdot \cos(3 \cdot t) - 1
Answer
D(t)=cos(3t)1D(t) = \cos(3t) - 1
Key Concept
Determining parameters of a sinusoidal function
Explanation
The amplitude, period, and phase shift of a sinusoidal function can be determined from given points on the function's graph. In this case, the amplitude is the maximum distance from the center, the period is related to the time it takes to reach the center from the farthest point, and the phase shift is zero since the function starts at the maximum point.

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