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Posted 2 months ago

Within a certain island population (that is in Hardy - Weinberg equilibrium) the frequency of the LL allele of the LML M blood group is 0.6 and the frequency of the MM allele is 0.4 . LL and MM alleles are co - dominant. There are 1000 people on the island. How many are heterozygous in this population?
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Answer from Sia
Posted 2 months ago
Calculate the frequency of the heterozygous genotype (Lm) using the Hardy-Weinberg equation: p2+2pq+q2=1p^2 + 2pq + q^2 = 1, where pp is the frequency of the L allele, qq is the frequency of the M allele, and 2pq2pq represents the frequency of the heterozygous genotype
Given p=0.6p = 0.6 and q=0.4q = 0.4, calculate 2pq2pq: 2pq=2×0.6×0.42pq = 2 \times 0.6 \times 0.4
Perform the calculation: 2pq=2×0.6×0.4=0.482pq = 2 \times 0.6 \times 0.4 = 0.48
Determine the number of heterozygous individuals by multiplying the frequency of the heterozygous genotype by the total population size: 0.48×10000.48 \times 1000
Perform the calculation: 0.48×1000=4800.48 \times 1000 = 480
Key Concept
Hardy-Weinberg equilibrium and heterozygote frequency calculation
The Hardy-Weinberg equation is used to calculate the expected frequency of genotypes in a population that is not evolving. The term 2pq2pq represents the frequency of heterozygous individuals. By multiplying this frequency by the total population size, we can determine the number of heterozygous individuals.

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