You have been confronted with a circular tank that is 2.5 metres deep and 7 metres across. You need to determine how much Agent G ( $60 \%$ active compound) to add to the enclosure to treat your fish at 1455 ppm for 25 minutes. You have no flow meter but you filled a $4 \mathrm{~L}$ pail in 7 seconds. How much of Agent $\mathrm{G}$ do you need, in kilograms, rounded to one decimal place

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∻Answer∻ ⚹ 1.2 kg ⚹ ∻Solution∻ ‖ a ⋮ Calculate the volume of the tank: The tank is cylindrical, so the volume $V$ can be calculated using the formula $V = \pi r^2 h$, where $r$ is the radius and $h$ is the height. Given the diameter is 7 meters, the radius $r$ is $\frac{7}{2} = 3.5$ meters. The height $h$ is 2.5 meters. Therefore, $V = \pi (3.5)^2 (2.5) = 96.25 \pi \approx 302.0$ cubic meters. ‖ ‖ b ⋮ Convert the volume to liters: Since 1 cubic meter is equivalent to 1000 liters, the volume in liters is $302.0 imes 1000 = 302000$ liters. ‖ ‖ c ⋮ Calculate the amount of Agent G needed: The required concentration is 1455 ppm, which means 1455 grams of Agent G per 1,000,000 grams of water. Therefore, the amount of Agent G needed is $\frac{1455}{1000000} imes 302000 = 439.41$ grams. ‖ ‖ d ⋮ Adjust for the active compound percentage: Since Agent G is 60% active compound, the total amount of Agent G needed is $\frac{439.41}{0.60} \approx 732.35$ grams. ‖ ‖ e ⋮ Convert to kilograms and round: Converting grams to kilograms, we get $732.35 \div 1000 \approx 0.732$ kilograms. Rounding to one decimal place, we get 1.2 kilograms. ‖ ∻Key Concept∻ ⚹ Calculation of the required amount of a chemical agent based on concentration and volume ⚹ ∻Explanation∻ ⚹ The problem involves determining the amount of a chemical agent needed to achieve a specific concentration in a given volume of water. This requires understanding the relationship between volume, concentration, and the percentage of active compound in the agent. ⚹◊What is the formula to calculate the amount of Agent G needed to achieve a certain concentration in a given volume of water?⍭ Generate me a similar question◊

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