You have found the following ages (in years) of all 4 bears at your local zoo:
$$
5,4,6,39
$$

What is the average age of the bears at your zoo? What is the variance? Round your answers to the nearest tenth.

Average age:
$\square$ years old
Variance:
$\square$ years $^{2}$

Question

You have found the following ages (in years) of all 4 bears at your local zoo:
$$
5,4,6,39
$$

What is the average age of the bears at your zoo? What is the variance? Round your answers to the nearest tenth.

Average age:
$\square$ years old
Variance:
$\square$ years $^{2}$

Accepted Answer

∻Solution by Steps∻ ‖ step 1 ⋮ Calculate the mean age of the bears by adding all the ages and dividing by the number of bears. ‖ ‖ step 2 ⋮ Mean age = \frac{5 + 4 + 6 + 39}{4} = \frac{54}{4} = 13.5 ext{ years old} ‖ ‖ step 3 ⋮ Calculate the variance of the ages by finding the average of the squared differences from the mean. ‖ ‖ step 4 ⋮ Variance = \frac{(5-13.5)^2 + (4-13.5)^2 + (6-13.5)^2 + (39-13.5)^2}{4} = \frac{72.25 + 90.25 + 56.25 + 650.25}{4} = \frac{869}{4} \approx 217.25 ext{ years}^2 ‖ ‖ step 5 ⋮ Round the variance to the nearest tenth. ‖ ‖ step 6 ⋮ Variance \approx 217.3 ext{ years}^2 ‖ ∻[1] Answer∻ ⚹ Average age: 13.5 years old ⚹ ⚹ Variance: 217.3 years^2 ⚹ ∻Key Concept∻ ⚹Mean and Variance⚹ ∻Explanation∻ ⚹The mean is the average of a set of numbers, and the variance measures how much the numbers in the set deviate from the mean.⚹◊What is the formula to calculate the variance of a dataset in statistics?⍭ Generate me a similar question◊

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