a $-3 x(7 x-4)=-21 x^{2}+12 x$

Q: a $-3 x(7 x-4)=-21 x^{2}+12 x$

∻Solution by Steps∻ ‖ step 1 ⋮ Start with the equation: $ -3x(7x - 4) = -21x^2 + 12x $ ‖ ‖ step 2 ⋮ Expand the left side: $ -21x^2 + 12x = -21x^2 + 12x $ ‖ ‖ step 3 ⋮ Set the equation to zero: $ -3x(7x - 4) + 21x^2 - 12x = 0 $ ‖ ‖ step 4 ⋮ Combine like terms: $ -21x^2 + 21x^2 - 12x + 12x = 0 $ ‖ ‖ step 5 ⋮ Factor the equation: $ -3x(7x - 4) = 0 $ ‖ ‖ step 6 ⋮ Solve for $ x $: $ x = 0 $ or $ 7x - 4 = 0 $ leading to $ x = \frac{4}{7} $ ‖ ∻Answer∻ ⚹ The solutions are $ x = 0 $ and $ x = \frac{4}{7} $ ⚹ ∻Key Concept∻ ⚹ Solving polynomial equations by factoring ⚹ ∻Explanation∻ ⚹ The equation was simplified and factored to find the roots, which are the values of $ x $ that satisfy the equation. ⚹◊How do you apply the product rule to differentiate the equation $-3x(7x - 4) = -21x^2 + 12x$?⍭ Generate me a similar question◊

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∻Solution by Steps∻ ‖ step 1 ⋮ Start with the equation: $ -3x(7x - 4) = -21x^2 + 12x $ ‖ ‖ step 2 ⋮ Expand the left side: $ -21x^2 + 12x = -21x^2 + 12x $ ‖ ‖ step 3 ⋮ Set the equation to zero: $ -3x(7x - 4) + 21x^2 - 12x = 0 $ ‖ ‖ step 4 ⋮ Combine like terms: $ -21x^2 + 21x^2 - 12x + 12x = 0 $ ‖ ‖ step 5 ⋮ Factor the equation: $ -3x(7x - 4) = 0 $ ‖ ‖ step 6 ⋮ Solve for $ x $: $ x = 0 $ or $ 7x - 4 = 0 $ leading to $ x = \frac{4}{7} $ ‖ ∻Answer∻ ⚹ The solutions are $ x = 0 $ and $ x = \frac{4}{7} $ ⚹ ∻Key Concept∻ ⚹ Solving polynomial equations by factoring ⚹ ∻Explanation∻ ⚹ The equation was simplified and factored to find the roots, which are the values of $ x $ that satisfy the equation. ⚹◊How do you apply the product rule to differentiate the equation $-3x(7x - 4) = -21x^2 + 12x$?⍭ Generate me a similar question◊

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