```
consider the five samples $(\mathrm{a}-\mathrm{e})$ described below:
which samples contains the greatest and smallest number of $\mathrm{H}$ atoms
a. $0.35 \mathrm{~mol} \mathrm{C} 2 \mathrm{H} 4$
b. $1 \times 10^{\wedge}-9 \mathrm{mg} \mathrm{H} 2$
c. $350 \mathrm{amu} \mathrm{NH} 3$
d. $6.0 \times 10^{\wedge} 23 \mathrm{H}$ atoms
e. $10 \mathrm{~g} \mathrm{H} 20$
```

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Answer from Sia

Posted 5 months ago

D

Key Concept

Avogadro's number and mole concept

Explanation

Sample D has $6.0 \times 10^{23}$ H atoms, which is Avogadro's number, representing one mole of H atoms, the largest finite number of H atoms among the options. To find the smallest number, we need to convert all samples to the number of H atoms and compare. Sample B, with $1 \times 10^{-9}$ mg of $\mathrm{H}_2$, will have the smallest number of H atoms because it is a minuscule mass compared to the other samples.

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