```
def F(n):
if n == 1: return 1
elif n == 2: return 1
else: return F(n-1) + F(n-2),so f(5) equal to what
```

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Answer from Sia

Posted 3 months ago

python

python

Explanation

The function F is defined to calculate the nth Fibonacci number recursively. The base cases return 1 for the first two numbers in the Fibonacci sequence. For all other cases, the function calls itself with the previous two numbers until it reaches the base cases. The main function tests the F function with two use cases to ensure it works correctly.

Step-by-step Instruction

▪

Include base cases for when n is 1 or 2, returning 1 as per the Fibonacci sequence

▪

For other cases, recursively call F with (n-1) and (n-2) and return their sum

▪

Define the main function to test the F function with specific use cases

▪

Use assert statements to verify the correctness of the F function for known Fibonacci numbers

Time Complexity

The time complexity of the recursive Fibonacci function is exponential, specifically O(2^n), because it makes two recursive calls for each non-base case.

Space Complexity

The space complexity is O(n) due to the maximum depth of the recursion call stack.

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