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fuzixin621's Question
Computer Science
Posted 3 months ago
def F(n):
if n == 1: return 1
elif n == 2: return 1
else: return F(n-1) + F(n-2),so f(5) equal to what
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Answer from Sia
Posted 3 months ago
The function F is defined to calculate the nth Fibonacci number recursively. The base cases return 1 for the first two numbers in the Fibonacci sequence. For all other cases, the function calls itself with the previous two numbers until it reaches the base cases. The main function tests the F function with two use cases to ensure it works correctly.
Step-by-step Instruction
Include base cases for when n is 1 or 2, returning 1 as per the Fibonacci sequence
For other cases, recursively call F with (n-1) and (n-2) and return their sum
Define the main function to test the F function with specific use cases
Use assert statements to verify the correctness of the F function for known Fibonacci numbers
Time Complexity
The time complexity of the recursive Fibonacci function is exponential, specifically O(2^n), because it makes two recursive calls for each non-base case.
Space Complexity
The space complexity is O(n) due to the maximum depth of the recursion call stack.

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