(e) A HashSet can contain duplicate elements. Question 2 [10 marks] (a) The boolean expression: $$ x50| |!(y50) \|(y50 \& \& y50| | y50) \& \&(y

Q: (e) A HashSet can contain duplicate elements. Question 2 [10 marks] (a) The boolean expression: \[ x>50| |!(y 50) \|(y 50 \& \& y 50| | y 50) \& \&(y<0))$ COMP 2020SEF / 8020SEF / S202W - Test 2

∻Solution by Steps∻ ‖ step 1 ⋮ The boolean expression given is $ x > 50 \lor \neg(y 50 \lor y \geq 0 $. ‖ ‖ step 2 ⋮ The expression $ \neg(y 50 \lor y \geq 0 $. ‖ ‖ step 3 ⋮ The expression $ x > 50 \lor y \geq 0 $ is equivalent to \( x > 50 \lor (y 50) \land (y 50) \land (y 50 || !(y

Question

(e) A HashSet can contain duplicate elements. Question 2 [10 marks] (a) The boolean expression: $$ x>50| |!(y<0) $$ is equivalent to which of the following expression: (i) ! $(!(x>50) \|(y<0))$ (ii) $x>50 \& \& y<0$ (iii) $x>50| | y<0$ (iv) ! $($ ! $(x>50) \& \&(y<0))$ COMP 2020SEF / 8020SEF / S202W - Test 2

Accepted Answer

∻Solution by Steps∻ ‖ step 1 ⋮ The boolean expression given is $ x > 50 \lor \neg(y < 0) $. We can rewrite this as $ x > 50 \lor y \geq 0 $. ‖ ‖ step 2 ⋮ The expression $ \neg(y < 0) $ is equivalent to $ y \geq 0 $, so we have $ x > 50 \lor y \geq 0 $. ‖ ‖ step 3 ⋮ The expression $ x > 50 \lor y \geq 0 $ is equivalent to $ x > 50 \lor (y < 0) $ being false, which leads us to $ \neg(\neg(x > 50) \land (y < 0)) $. ‖ ‖ step 4 ⋮ Therefore, the equivalent expression can be represented as $ \neg(\neg(x > 50) \land (y < 0)) $, which matches option (iv). ‖ ***D*** ∻Key Concept∻ ⚹Logical equivalence in boolean expressions⚹ ∻Explanation∻ ⚹Understanding how to manipulate and simplify boolean expressions is crucial for determining their equivalence. In this case, we used negation and logical operators to find the correct equivalent expression.⚹◊What is the truth table for the boolean expression $x > 50 || !(y < 0)$?⍭ Generate me a similar question◊

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