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Posted 3 months ago
ddx[3cos(x)+4x2]=\frac{d}{d x}\left[3 \cos (x)+4 x^{2}\right]=
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Answer from Sia
Posted 3 months ago
Solution by Steps
step 1
Apply the product rule to differentiate 3cos(x)+4x23 \cos(x) + 4 x^2
step 2
Differentiate 3cos(x)3 \cos(x) to get 3sin(x)-3 \sin(x)
step 3
Differentiate 4x24 x^2 to get 8x8x
step 4
Combine the derivatives to get the final result: 3sin(x)+8x-3 \sin(x) + 8x
3sin(x)+8x-3 \sin(x) + 8x
Key Concept
Differentiation of trigonometric and polynomial functions
The derivative of a sum of functions is the sum of the derivatives of each function. The derivative of cos(x)\cos(x) is sin(x)-\sin(x), and the derivative of x2x^2 is 2x2x. The constants are multiplied accordingly.

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