$\frac{d}{d x}\left[3 \cos (x)+4 x^{2}\right]=$

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∻Solution by Steps∻ ‖ step 1 ⋮ Apply the product rule to differentiate $3 \cos(x) + 4 x^2$. ‖ ‖ step 2 ⋮ Differentiate $3 \cos(x)$ to get $-3 \sin(x)$. ‖ ‖ step 3 ⋮ Differentiate $4 x^2$ to get $8x$. ‖ ‖ step 4 ⋮ Combine the derivatives to get the final result: $-3 \sin(x) + 8x$. ‖ ∻Answer∻ ⚹ $-3 \sin(x) + 8x$ ⚹ ∻Key Concept∻ ⚹Differentiation of trigonometric and polynomial functions⚹ ∻Explanation∻ ⚹The derivative of a sum of functions is the sum of the derivatives of each function. The derivative of $\cos(x)$ is $-\sin(x)$, and the derivative of $x^2$ is $2x$. The constants are multiplied accordingly.⚹◊What is the derivative of $3\cos(x) + 4x^{2}$ with respect to $x$?⍭ Generate me a similar question◊

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