how many protons, nuetrons and electrons in ion $200 \mathrm{Au}+$

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∻Solution∻ ‖ 1 ⋮ **Identify the element**: The given ion is $^{200}\mathrm{Au}^+$. Gold (Au) is the element in question, and its atomic number is 79. ‖ ‖ 2 ⋮ **Determine the number of protons**: The atomic number of gold (Au) is 79, which means that a neutral gold atom has 79 protons. The number of protons does not change in an ion, so $^{200}\mathrm{Au}^+$ also has 79 protons. ‖ ‖ 3 ⋮ **Determine the number of electrons**: Since the ion has a $1+$ charge, it means it has lost one electron. Therefore, the number of electrons in $^{200}\mathrm{Au}^+$ is 79 (the number of protons) minus 1, which equals 78 electrons. ‖ ‖ 4 ⋮ **Determine the number of neutrons**: The mass number of gold in this ion is 200. The number of neutrons is found by subtracting the atomic number from the mass number: $200 - 79 = 121$ neutrons. ‖ ∻Answer∻ ⚹ Protons: 79, Neutrons: 121, Electrons: 78 ⚹ ∻Key Concept∻ ⚹ Atomic number and mass number are used to determine the number of protons, neutrons, and electrons in an ion. ⚹ ∻Explanation∻ ⚹ The atomic number gives the number of protons (and electrons in a neutral atom), the mass number minus the atomic number gives the number of neutrons, and the charge indicates the loss or gain of electrons. ⚹◊What is the atomic number of the ion $^{200}Au^{+}$?⍭ Generate me a similar question◊

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