$\lim _{x \rightarrow 0^{+}} \frac{\ln x}{x}$

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∻Solution by Steps∻ ‖ step 1 ⋮ Evaluate the limit of $\frac{\ln(x)}{x}$ as $x$ approaches $0$ from the positive side. ‖ ‖ step 2 ⋮ Recognize that as $x$ approaches $0^+$, $\ln(x)$ approaches $-\infty$ and $x$ approaches $0$. ‖ ‖ step 3 ⋮ Consider the behavior of the function: the numerator goes to $-\infty$ faster than the denominator goes to $0$. ‖ ‖ step 4 ⋮ Conclude that the limit $\lim_{x o 0^+} \frac{\ln(x)}{x}$ is $-\infty$. ‖ ∻Answer∻ ⚹ $-\infty$ ⚹ ∻Key Concept∻ ⚹Limits involving natural logarithms as the argument approaches zero⚹ ∻Explanation∻ ⚹As $x$ approaches $0$ from the positive side, the natural logarithm of $x$ becomes very large in the negative direction much faster than $x$ approaches zero, causing the fraction to approach negative infinity.⚹◊What is the limit of $\frac{\ln x}{x}$ as $x$ approaches $0^{+}$?⍭ Generate me a similar question◊

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