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15240672380's Question
Posted 3 months ago

N2O4(l)+2 N2H4(l)3 N2( g)+4H2O(g)\mathrm{N}_{2} \mathrm{O}_{4}(\mathrm{l})+2 \mathrm{~N}_{2} \mathrm{H}_{4}(\mathrm{l}) \rightarrow 3 \mathrm{~N}_{2}(\mathrm{~g})+4 \mathrm{H}_{2} \mathrm{O}(\mathrm{g}) hydrarine

Which substance acts as the reducing agent?
N2H4\overline{\mathrm{N}_{2} \mathrm{H}_{4}}
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Answer from Sia
Posted 3 months ago
Key Concept
Reducing Agent
In the given reaction, N2H4\mathrm{N_2H_4} (hydrazine) is the reducing agent because it donates electrons to N2O4\mathrm{N_2O_4}, resulting in its reduction to N2\mathrm{N_2}, while N2H4\mathrm{N_2H_4} itself gets oxidized to H2O\mathrm{H_2O}.

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