Sia

Based on the given function $f(x) = x^5 + x^3 + x$, we need to find the value of $\frac{d}{dx}[f^{-1}(3)]$. To do this, we first need to find $f^{-1}(3)$. By setting $f(a) = 3$, we can solve for $a$ such that $a^5 + a^3 + a = 3$. Once we find the value of $a$, we can then calculate $\frac{d}{dx}[f^{-1}(3)] = \frac{1}{5a^4 + 3a^2 + 1}$. Let's work through the steps to find the value together!