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CHEM2522 · Sustainable Chemical Manufacture

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Chapter 1 of 13 · CHEM2522

Green Chemistry & Green Metrics

Week 1 of University of Sydney CHEM2522 sets the frame for the whole unit: the 12 principles of green chemistry and the quantitative metrics that turn 'greener' into a number. You learn to score a synthesis by atom economy, E-factor, effective mass yield and % ideality, and to critique a real route (the classic ibuprofen synthesis) against the principles. These metrics recur all semester and are examinable as datasheet-formula calculations plus commentary.

In this chapter

What this chapter covers

  • 01The 12 principles of green chemistry (1998): prevention, atom economy, catalysis, renewable feedstocks, design for degradation and more
  • 02Atom economy = (M of product ÷ M of all reagents) × 100 — high for addition/rearrangement/catalytic, low for substitution/elimination
  • 03E-factor = mass of waste ÷ mass of product; typical values from oil refining (~0.1) to pharmaceuticals (25-100)
  • 04Effective mass yield EMY = (mass product ÷ mass of non-benign reagents & by-products) × 100 (Hudlicky's 'benign' is subjective)
  • 05% ideality = (construction + strategic redox steps ÷ total steps) × 100 (Baran); the 'ideal synthesis' (Hendrickson)
  • 06Step economy — every step generates waste, so fewer steps means less waste
  • 07Critiquing a route: the original 8-step ibuprofen synthesis vs a shorter catalytic Pd/CO route
Worked example · free

Atom economy: substitution vs addition route to ethanol

Q [4 marks]. Ethanol can be made two ways. Route A is the substitution of bromoethane with hydroxide: C2H5Br (M = 108.97) + NaOH (M = 40.00) → C2H5OH (M = 46.07) + NaBr (M = 102.89). Route B is the acid-catalysed hydration of ethene: C2H4 (M = 28.05) + H2O (M = 18.02) → C2H5OH (M = 46.07). Calculate the atom economy of each and say which is greener on this metric and why. (4 marks)
  • +1Use atom economy = (M of desired product ÷ M of all reagents) × 100, with the catalyst disregarded.
  • +1Route A (substitution): reagent mass = 108.97 + 40.00 = 148.97. AE = (46.07 ÷ 148.97) × 100 = 30.9%. Most of the mass leaves as the NaBr by-product.
  • +1Route B (addition): reagent mass = 28.05 + 18.02 = 46.07. AE = (46.07 ÷ 46.07) × 100 = 100%. Every atom of the reagents ends up in the product.
  • +1Conclusion: Route B is far greener on atom economy (100% vs 30.9%). Addition reactions incorporate all reagent atoms, whereas the substitution sheds a bromide leaving group as waste — the general rule that additions/rearrangements score high and substitutions/eliminations score low.
Route A (substitution) atom economy = 46.07 ÷ 148.97 × 100 = 30.9%; Route B (hydration/addition) = 46.07 ÷ 46.07 × 100 = 100%. Route B is greener on this metric because an addition incorporates every reagent atom into the product, while the substitution discards a bromide leaving group (as NaBr) that carries most of the mass.
Sia tip — Atom economy is decided by reaction type before you touch a number: additions, rearrangements and catalytic couplings can reach 100%, substitutions and eliminations cannot because they shed a leaving group. Ask Sia to sort a list of reactions by expected atom economy and explain each call — it walks the reasoning, it never just hands over the answer.
Glossary

Key terms

Atom economy
(M of the desired product ÷ M of all reagents) × 100, catalyst disregarded. A best-case, on-paper mass metric; highest for addition, rearrangement and catalytic reactions, lowest for substitutions and eliminations that lose a leaving group.
E-factor
Mass of waste ÷ mass of desired product. Waste includes by-products, unreacted starting material, spent solvent and purification media. Sheldon's ladder: oil refining ~0.1, bulk chemicals 1-5, fine chemicals 5-50, pharmaceuticals 25-100.
Effective mass yield (EMY)
(mass of product ÷ mass of non-benign reagents and by-products) × 100. Credits reagents judged environmentally benign (e.g. water, dilute ethanol); 'benign' (Hudlicky) is a subjective call.
% ideality
(number of construction + strategic redox steps ÷ total steps) × 100 (Baran). Rewards steps that build the target skeleton or set required oxidation state, and penalises protecting-group and functional-group-interconversion steps.
Ideal synthesis
Hendrickson's goal: unite the building blocks in one step, with every reagent atom in the product and correct chemo-, regio- and stereoselectivity, using no protecting groups or redundant redox steps.
Step economy
The principle that each synthetic step generates its own waste, so a shorter route is usually greener; a driver behind cascade and one-pot reactions.
FAQ

Green Chemistry & Green Metrics FAQ

What is the difference between atom economy and E-factor?

Atom economy is a best-case calculation on the balanced equation — the fraction of reagent mass that ends up in the product if the reaction goes perfectly — so it depends only on the chemistry, not on how the reaction is run. The E-factor is a real measurement: total waste mass divided by product mass, including yield losses, unreacted reagents, solvents and workup media. A route can have a high atom economy and still a poor E-factor because solvent and purification waste dominate real processes; both appear on the exam data sheet because they answer different questions.

Do I have to memorise the green-metric formulas for the CHEM2522 exam?

No — the exam provides a data sheet with the 12 principles, the greenness formulas (atom economy, E-factor, EMY, % ideality) and the molar-mass-average formulas, plus a periodic table. So practise applying them with correct units and a sanity check rather than reciting them. Confirm the exact contents of the data sheet and whether a calculator is permitted on Canvas.

Why is the E-factor so much higher for pharmaceuticals than for oil refining?

Because fine and pharmaceutical syntheses are many-step, low-throughput and heavily reliant on solvent-intensive purification (chromatography, recrystallisation, aqueous washes), all of which count as waste. Sheldon's figures put oil refining near 0.1, bulk chemicals at 1-5 and pharmaceuticals at 25-100 kg of waste per kg of product — the more complex and the more chromatography, the higher the E-factor.

Can AI help me with the green-metric calculations?

Yes. Sia can set up an atom-economy or E-factor calculation with you, show which masses belong in which formula, and check your units and arithmetic on a practice route, then explain why a high atom economy can still hide a poor E-factor. Use it to rehearse the method on tutorial-style questions; it does not complete graded work for you, and University of Sydney academic-integrity rules apply.

Study strategy

Exam move

Anchor Week 1 on the two metrics you will use all semester: atom economy (decided by reaction type — additions high, substitutions low) and the E-factor (decided by real waste, so always worse than atom economy suggests). Work at least one route through both on the same numbers so the gap between them becomes intuitive. Learn the 12 principles as a checklist you can apply to a route critique (the ibuprofen example is the template: count steps, spot the atoms that never make it into the product, flag hazardous reagents and protecting-group waste). Because the exam gives you the data-sheet formulas, spend your time on setup and interpretation, not memorisation, and always state units. This chapter's methods reappear in every later 'is this process green?' question, so make the atom-economy-vs-E-factor argument automatic.

Working through Green Chemistry & Green Metrics in CHEM2522? Sia is AskSia’s AI Chemistry tutor — ask any CHEM2522 Green Chemistry & Green Metrics question and get a clear, step-by-step explanation grounded in how CHEM2522 is taught and assessed. Read this chapter free, then take your hardest questions to Sia.

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