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CHEM2522 · Sustainable Chemical Manufacture

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Chapter 4 of 13 · CHEM2522

Transition-Metal Cross-Coupling Catalysis

Week 4 builds the single most examinable mechanism in the process half of CHEM2522: the palladium cross-coupling cycle. You learn the general Pd(0)/Pd(II) loop — oxidative addition, transmetalation, isomerisation, reductive elimination — and the family of named couplings (Kumada, Suzuki-Miyaura, Negishi, Sonogashira, Stille, Heck, Buchwald-Hartwig) that build C-C and C-N bonds in real drug syntheses. Exam questions ask you to name the three cycle steps, predict a coupling product and explain the role of the base, LiCl or copper co-catalyst.

In this chapter

What this chapter covers

  • 01Catalysis basics: a catalyst lowers activation energy, is not consumed and does not shift equilibrium; homogeneous vs heterogeneous
  • 02The 18-electron rule (Pd(PPh3)4 is 18e, coordinatively saturated → must lose a ligand first)
  • 03The general cycle: oxidative addition (Pd(0)→Pd(II)) → transmetalation → cis/trans isomerisation → reductive elimination (Pd(II)→Pd(0))
  • 04Oxidative-addition reactivity of the C-X bond: I > OTf > Br >> Cl
  • 05Named couplings by transmetalating partner: Kumada (Mg), Suzuki (B, needs base), Negishi (Zn), Sonogashira (alkyne + CuI), Stille (Sn, LiCl helps)
  • 06Buchwald-Hartwig C-N coupling: amine coordination + base deprotonation replace transmetalation
  • 07Heck reaction: carbometalation (syn addition across an alkene) then beta-hydride elimination; halide partner needs no beta-H
  • 08Predicting the product of a coupling in a drug synthesis
Worked example · free

Predict a Suzuki-Miyaura product and name the cycle steps

Q [4 marks]. 4-bromotoluene is coupled with phenylboronic acid using a Pd(0) catalyst and a base (aqueous K2CO3). (a) Give the coupled product. (b) Name the three core steps of the catalytic cycle in order and say where the base acts. (c) Why is a base essential for Suzuki but not for Kumada? (4 marks)
  • +1Identify the new bond: a Suzuki-Miyaura coupling joins the aryl of the aryl halide to the aryl of the boronic acid, forming a biaryl C-C bond. Product = 4-methylbiphenyl.
  • +1Cycle step 1 - oxidative addition: Pd(0) inserts into the C-Br bond of 4-bromotoluene to give an aryl-Pd(II)-Br complex (Pd goes 0 → +2).
  • +1Cycle step 2 - transmetalation: the base activates the boronic acid as a boronate and helps displace bromide, transferring the phenyl group from boron to palladium; then step 3 - reductive elimination forges the aryl-aryl bond and regenerates Pd(0).
  • +1Base role: in Suzuki, the base is essential because it both forms the reactive boronate (boron is otherwise too weakly nucleophilic) and displaces halide to enable transmetalation. Kumada uses a Grignard (Mg), which is already strongly nucleophilic, so it transmetalates without added base.
(a) 4-methylbiphenyl. (b) Oxidative addition (Pd(0) → Pd(II) into the C-Br bond) → transmetalation (phenyl transferred from boron to Pd, assisted by the base) → reductive elimination (forms the biaryl and returns Pd(0)); the base acts in the transmetalation step. (c) Suzuki needs a base to make the weakly nucleophilic boronic acid into a reactive boronate and to displace halide; Kumada's Grignard is nucleophilic enough to transmetalate without base.
Sia tip — For any named coupling, name the transmetalating metal (Mg/B/Zn/Cu/Sn) and ask what activates it — base for Suzuki, CuI for Sonogashira, LiCl for Stille. Then the three-step cycle is the same each time. Ask Sia to quiz you on 'which coupling, which additive, what product' across a set of drug syntheses; it explains each cycle step rather than just giving the biaryl.
Glossary

Key terms

Oxidative addition
The first step of the Pd cycle: Pd(0) inserts into a carbon-halogen (or C-OTf) bond, raising palladium from 0 to +2. Reactivity of the C-X bond runs I > OTf > Br >> Cl.
Transmetalation
Transfer of the organic group from a main-group or late-metal partner (Mg, B, Zn, Cu, Sn) onto palladium, with retention of stereochemistry through a four-centred transition state. For Suzuki it requires a base; for Stille, LiCl accelerates it.
Reductive elimination
The bond-forming step: two cis groups on Pd(II) couple to make the new C-C (or C-N) bond and return palladium to Pd(0), closing the cycle.
18-electron rule
The stability guideline for transition-metal complexes; Pd(PPh3)4 is an 18-electron, coordinatively saturated complex that must shed a ligand before it can bind a substrate.
Suzuki-Miyaura coupling
Pd-catalysed coupling of an aryl/vinyl halide with an organoboron partner; requires a base to form the reactive boronate and to enable transmetalation. Widely used for biaryls in pharmaceuticals.
Heck reaction
Pd-catalysed coupling of an aryl/vinyl halide with an alkene via carbometalation (syn addition of C and Pd across the alkene) then beta-hydride elimination, giving a new substituted alkene; the halide partner must have no beta-hydrogens.
FAQ

Transition-Metal Cross-Coupling Catalysis FAQ

What is the difference between the named cross-couplings?

They share the same Pd(0)/Pd(II) cycle and differ mainly in the transmetalating partner and its activator: Kumada uses a Grignard (Mg, no base needed), Suzuki-Miyaura uses an organoboron (needs a base to form the boronate), Negishi uses an organozinc, Sonogashira couples a terminal alkyne with a copper(I) co-catalyst and an amine base, and Stille uses an organostannane (LiCl accelerates transmetalation, but tin is toxic). Buchwald-Hartwig makes C-N bonds by having the amine coordinate and a base deprotonate instead of a transmetalation. Learn the cycle once, then tabulate the partner and additive for each.

Why does oxidative-addition reactivity go I > OTf > Br >> Cl?

Oxidative addition breaks the C-X bond, and weaker C-X bonds react faster. C-I is the weakest and most easily inserted, C-Cl the strongest and slowest (which is why aryl chlorides need specially designed electron-rich, bulky ligands). In the exam, use this order to pick which halide couples preferentially in a substrate that has more than one.

Why does the Heck halide partner need no beta-hydrogen?

Because the Heck mechanism ends with beta-hydride elimination to form the new alkene. If the organohalide partner itself carried a beta-hydrogen, the palladium could eliminate prematurely from the wrong carbon, giving side products and destroying the coupling. So Heck partners are typically aryl or vinyl halides, which have no available beta-hydrogen on the carbon bearing palladium.

Can Sia help me learn the Pd cross-coupling cycle?

Yes. Sia can draw you through oxidative addition, transmetalation and reductive elimination for a specific coupling, quiz you on which additive each named reaction needs, and check your product prediction on a drug-synthesis example. It explains each step and checks your reasoning; it does not complete graded assessment, and University of Sydney academic-integrity rules apply.

Study strategy

Exam move

Master one cycle and reuse it: draw oxidative addition → transmetalation → reductive elimination from memory, with Pd changing 0 → +2 → 0, and be able to place the base (Suzuki), copper co-catalyst (Sonogashira) or LiCl (Stille) at the transmetalation step. Build a small table of the named couplings — partner metal, activator, typical use — because the multiple-choice section rewards fast recall of 'which coupling is this'. Keep the Heck reaction separate in your mind (carbometalation + beta-hydride elimination, no transmetalation) and remember the C-X reactivity order I > OTf > Br >> Cl for selectivity questions. Practise product prediction on the Week 4 tutorial drug syntheses (boscalid, losartan and friends) so you can both name the coupling and draw the product under time pressure.

Working through Transition-Metal Cross-Coupling Catalysis in CHEM2522? Sia is AskSia’s AI Chemistry tutor — ask any CHEM2522 Transition-Metal Cross-Coupling Catalysis question and get a clear, step-by-step explanation grounded in how CHEM2522 is taught and assessed. Read this chapter free, then take your hardest questions to Sia.

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