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Sia

Question
Biology
Posted 7 months ago

A template strand of DNA in a gene reads:
3′3^{\prime} TCT CCA AGC 5′5^{\prime}
Second letter
[i]
\begin{tabular}{|c|c|c|c|c|c|c|}
\hline & U\mathbf{U} & C & & A & G\mathbf{G} & \\
\hline U\mathbf{U} & \begin{tabular}{l}
\begin{tabular}{l} 
UUU \\
UUC
\end{tabular} Phe \\
UUA }\} Leu
\end{tabular} & \begin{tabular}{l} 
UCU \\
UCC \\
UCA \\
UCG
\end{tabular} & Ser & \begin{tabular}{l}
 UAU  UAC }Tyr\left.\begin{array}{l}\text { UAU } \\
\text { UAC }\end{array}\right\} \mathrm{Tyr} \\
UAA Stop \\
UAG Stop
\end{tabular} & \begin{tabular}{l}
 UGU  UGC }\left.\begin{array}{l}\text { UGU } \\
\text { UGC }\end{array}\right\} Cys \\
UGA Stop \\
UGG Trp
\end{tabular} & \begin{tabular}{l}
\begin{tabular}{l} 
U \\
C \\
A \\
G
\end{tabular}
\end{tabular} \\
\hline C & \begin{tabular}{l}
 CUU  CUC  CUG }\left.\begin{array}{l}\text { CUU } \\
\text { CUC } \\
\text { CUG }\end{array}\right\} Leu
\end{tabular} & \begin{tabular}{l}
 CCU  CCC  CCA  CCG ]\left.\begin{array}{l}\text { CCU } \\
\text { CCC } \\
\text { CCA } \\
\text { CCG }\end{array}\right]
\end{tabular} & Pro & \begin{tabular}{l}
 CAU  CAC }\left.\begin{array}{l}\text { CAU } \\
\text { CAC }\end{array}\right\} His \\
CAA }\} GIn
\end{tabular} & \begin{tabular}{l}
 CGU  CGC  CGA  CGG }\left.\begin{array}{l}\text { CGU } \\
\text { CGC } \\
\text { CGA } \\
\text { CGG }\end{array}\right\} Arg
\end{tabular} & \begin{tabular}{l}
\begin{tabular}{l} 
U \\
C \\
A \\
G
\end{tabular}
\end{tabular} \\
\hline A & \begin{tabular}{l}
 AUU  AUC  AUA }\left.\begin{array}{l}\text { AUU } \\
\text { AUC } \\
\text { AUA }\end{array}\right\} Ile \\
AUG Met
\end{tabular} & \begin{tabular}{l}
ACUACCACAACG}\left.\begin{array}{l}\mathrm{ACU} \\
\mathrm{ACC} \\
\mathrm{ACA} \\
\mathrm{ACG}\end{array}\right\}
\end{tabular} & Thr & \begin{tabular}{l}
 AAU  AAC  AAA  AAG }\left.\begin{array}{l}\text { AAU } \\
\text { AAC } \\
\text { AAA } \\
\text { AAG }\end{array}\right\} Lys
\end{tabular} & \begin{tabular}{l}
 AGU  AGC  AGA  AGG }\left.\begin{array}{l}\text { AGU } \\
\text { AGC } \\
\text { AGA } \\
\text { AGG }\end{array}\right\} Arg
\end{tabular} & \begin{tabular}{l}
\begin{tabular}{l} 
U \\
C \\
A \\
G
\end{tabular}
\end{tabular} \\
\hline G & \begin{tabular}{l}
 GUU  GUC  GUG }\left.\begin{array}{l}\text { GUU } \\
\text { GUC } \\
\text { GUG }\end{array}\right\} Val
\end{tabular} & \begin{tabular}{l}
 GCU  GCC  GCA  GCG }\left.\begin{array}{l}\text { GCU } \\
\text { GCC } \\
\text { GCA } \\
\text { GCG }\end{array}\right\}
\end{tabular} & Ala & \begin{tabular}{l}
 GAU  GAC }\left.\begin{array}{l}\text { GAU } \\
\text { GAC }\end{array}\right\} Asp
\end{tabular} & \begin{tabular}{l}
 GGU  GGC  GGA }\left.\begin{array}{l}\text { GGU } \\
\text { GGC } \\
\text { GGA }\end{array}\right\} Gly
\end{tabular} & \begin{tabular}{l}
\begin{tabular}{l} 
U \\
C \\
A \\
G
\end{tabular}
\end{tabular} \\
\hline
\end{tabular}

Image from OpenStax, CC BY 3.0.
Using the codon chart, what is the sequence of amino acids that is produced after translation?

Choose 1 answer:
(A) Arg - Ser - Gly
(B) Ser - Gly - Leu
(c) Arg-Gly-Ser
(D) Ser - Gly - Gly
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Answer from Sia
Posted 7 months ago
D
Key Concept
Codon Chart Usage
Explanation
To determine the sequence of amino acids, first transcribe the DNA template strand to mRNA, then use the codon chart to translate the mRNA codons into amino acids.

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