Queensland University of Technology · S1 2027 · FACULTY OF ENGINEERING

EGB375 · Design of Concrete Structures

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Design of Concrete Structures

— Every capacity check, every AS3600 clause, every mark — reinforced and prestressed concrete design worked end to end for the QUT exam.

EGB375 Design of Concrete Structures is a third-year civil-engineering unit at Queensland University of Technology, worth 12 credit points, taught in the Faculty of Engineering and graded on GPA (QUT's 7-point grade-point average). It is the reinforced- and prestressed-concrete design unit of the program, governed throughout by the Australian Standard AS3600-2018. It carries you from the equivalent rectangular stress block through the ultimate moment and shear capacity of beams, then serviceability, slabs, columns and isolated footings, always as a design calculation rather than pure theory. This free guide mirrors how EGB375 is assessed at Queensland University of Technology and works every element end to end for the closed-book final that decides half the unit mark.

EGB375 · Queensland University of Technology
Contents · the whole subject, one map

What EGB375 covers

Twelve chapters walk EGB375 from the equivalent stress block through reinforced- and prestressed-concrete flexure, shear, serviceability, slabs, columns and footings — every element worked to AS3600-2018 for the QUT final.

01Concrete & Steel Materials + Equivalent Rectangular Stress BlockAS3600 8.1.2/3.1.4 assumptions; alpha2 & gamma factors; fsy=500, ecu=0.003, Es=200GPa; N/L bars; bar areas02Singly Reinforced Beam — Ultimate Moment Capacity & Flexural DesignC=T equilibrium, dn, Z=d-gamma*dn/2, Mu=Ast*fsy*Z, ductility kuo<=0.36, phi=0.85, design-for-Ast03Doubly Reinforced Beams & T-BeamsCc+Cs=T quadratic for dn, compression-steel strain check; T-beam flange test Cf vs T, rectangular vs T action04Prestressed Concrete — Mechanics, Allowable Stresses & Magnel Methodeccentric fibre stresses (tension +ve), transfer/service stages, allowable fci/fti/fc/ft, Magnel 4 equations, parabolic tendon05PSC — Losses, Tendon Sizing & Ultimate Flexural Capacitylosses 10%/20%, jacking force & strand count, sigma_pu=fpb(1-k1k2/gamma), dn, Mu for fully/partially prestressed06Shear Design of RC & PSC Beams (AS3600 MCFT)dv=max(0.72D,0.9d), ex mid-depth strain, theta_v=29+7000ex, Vu,max web crushing, Vuc=kv*bv*dv*sqrt(fc), Vus stirrups, min stirrups & torsion spacing07Serviceability I — Crack Width & Spacingshrinkage strain & residual stress, cracking stress fct.f=0.6sqrt(fc), tension chord hc,eff, Sr,max, Wcr<=w'max08Serviceability II — Steel Stresses, Section Inertia & DeflectionMcr, gross/cracked transformed section Ig/Icr, Ief tension stiffening, sigma_scr, 10M-method deflection, kcs, span/250 & span/500 limits09RC Slabs — One-Way & Two-Way + Deemed-to-Comply Deflectionaspect ratio Ly/Lx, span/depth Lef/d formula (k3,k4,Fd,ef), coefficient method Mx=bx*q*Lx^2, min & crack-control steel, corner mesh10RC Column Sections — Interaction Diagram (Points A-D)squash Nuo, decompression B, balanced C (dn=0.545d), pure bending D; plastic centroid; phi=0.6/0.65 compression, up to 0.85 bending11Slender Columns — Slenderness & Moment Magnificationr=0.3D, Le=kLu, short/slender limit Le/r, Euler-type Nc, magnifier delta_b=km/(1-N*/Nc), km=0.6-0.4(M1/M2), Mmax=delta*M212Shallow (Isolated Pad) Footing Designqa,net bearing/size, punching shear fcv & Vuo at dom/2, flexure at 0.7asup, flexural shear at dv; four checks (service size, ultimate strength)
Assessment

How EGB375 is assessed

ComponentWeightFormat
Self-assessed Homework Reflection10%Single end-of-semester self-assessment form (student awards own grade 1-10 across ~11 weekly HW problems + 100-word justification), Week 13
Design Project — Oral Poster Presentation15%Group of 4, out of 15 marks (10 group presentation + 5 individual Q&A), Week 7
Design Project — Written Report25%Individual written report out of 25 marks, Week 11
Final Exam50%Closed-book, paper-based, out of 100, QUT Central Examinations; five A4 double-sided student-prepared note sheets permitted (handwritten, typed, or a mix); duration not stated
Worked example · free

Ultimate moment capacity of a singly reinforced beam (AS3600-2018)

Q [10 marks]. A singly reinforced rectangular beam has width b = 250 mm, overall depth D = 500 mm and effective depth d = do = 450 mm (one tension layer of 3N20, Ast = 3 x 310 = 930 mm2), with f'c = 32 MPa and fsy = 500 MPa. Determine the ultimate moment capacity Mu and the design capacity phi.Mu.
  • +2Stress-block factors (grade-dependent): alpha2 = 0.85 - 0.0015(32) = 0.802; gamma = 0.97 - 0.0025(32) = 0.89 (both >= 0.67, so valid).
  • +1Steel tension (steel assumed yielded): T = Ast.fsy = 930 x 500 = 465 000 N = 465 kN.
  • +2Neutral axis from horizontal equilibrium C = T: dn = T / (alpha2.f'c.gamma.b) = 465 000 / (0.802 x 32 x 0.89 x 250) = 465 000 / 5710 = 81.4 mm.
  • +2Ductility gate: kuo = dn/do = 81.4/450 = 0.181 <= 0.36 (ductile); strain check eps_st = 0.003(450 - 81.4)/81.4 = 0.0136 >= 0.0025, so the steel has yielded and T = Ast.fsy holds.
  • +1Lever arm of the internal couple: Z = d - gamma.dn/2 = 450 - 0.89 x 81.4/2 = 450 - 36.2 = 413.8 mm.
  • +1Moment capacity: Mu = T.Z = 465 000 N x 413.8 mm = 1.924 x 10^8 N.mm = 192.4 kN.m.
  • +1Design capacity for bending (phi = 0.85): phi.Mu = 0.85 x 192.4 = 163.5 kN.m, to be compared with the factored moment M*.
Mu = 192.4 kN.m; phi.Mu = 163.5 kN.m (design adequate provided phi.Mu >= M*). The section is under-reinforced and ductile (kuo = 0.181 <= 0.36).
Sia tip — Keep every number in newtons and millimetres so the moment lands in N.mm, then divide by 10^6 once at the end for kN.m. Always recompute alpha2 and gamma for the actual grade and show the kuo <= 0.36 ductility check before you quote Mu.
Glossary

Key terms

Equivalent rectangular stress block
The AS3600 idealisation of the concrete compression zone as a uniform stress alpha2.f'c acting over a depth gamma.dn from the compression face, replacing the true curved stress distribution.
alpha2 and gamma
Grade-dependent stress-block factors: alpha2 = 0.85 - 0.0015 f'c >= 0.67 and gamma = 0.97 - 0.0025 f'c >= 0.67 (e.g. 0.802 and 0.89 at f'c = 32 MPa).
Neutral axis depth dn
The depth from the compression face to the level of zero strain, found from horizontal equilibrium C = T; dn = Ast.fsy / (alpha2.f'c.gamma.b) for a singly reinforced section.
Lever arm Z
The distance between the concrete compression resultant and the steel tension resultant, Z = d - gamma.dn/2; the moment capacity is the couple T.Z.
Ductility ratio kuo
kuo = dn/do; AS3600 requires kuo <= 0.36 so the section is under-reinforced and the steel yields (warns) before the concrete crushes.
Capacity reduction factor phi
The strength-reduction factor applied to nominal capacity: phi = 0.85 for bending, 0.75 for shear with N-type fitments, 0.7 for footing punching, 0.6 (0.65 short) for column compression.
Prestress ultimate stress sigma_pu
The tendon stress at ultimate, sigma_pu = fpb(1 - k1.k2/gamma), used with the neutral-axis depth to find the prestressed moment capacity Mu.
Shear depth dv
The effective shear (lever-arm) depth, dv = max(0.72D, 0.9d), at which V* and M* are taken and used in the MCFT-based shear equations.
Strut angle theta_v
The compression-strut inclination in the MCFT shear model, theta_v = 29 + 7000.eps_x, where eps_x is the mid-depth longitudinal strain.
Effective second moment Ief
The tension-stiffening inertia used for deflection, Ief = Icr / [1 - (1 - Icr/Ig)(Mcr/M*)^2] <= Ig, interpolating between cracked and gross behaviour.
Interaction diagram
The column strength envelope in (M, N) space defined by Points A (squash), B (decompression), C (balanced, dn = 0.545d) and D (pure bending); the design point (M*, N*) must lie inside the factored curve.
Moment magnifier delta_b
The slender-column factor delta_b = km/(1 - N*/Nc) >= 1.0 that amplifies the design moment to Mmax = delta_b.M2* once Le/r exceeds the short-column limit.
Punching shear
The two-way shear check on a footing or slab around a column, at a critical perimeter u a distance dom/2 from the face; require V*punch <= phi.Vuo with fcv <= 0.34.sqrt(f'c).
AS3600-2018
The Australian Standard for Concrete Structures that governs every design factor, capacity equation and detailing rule examined in EGB375.
FAQ

EGB375 FAQ

Can AI help me study EGB375?

Yes. Sia is an AI study tutor that explains EGB375 topics step by step, so you can ask it to walk through the C = T to dn to ductility to Z to Mu flexure workflow, the MCFT shear procedure, or a column interaction check, and have it show each AS3600 step and unit conversion. It is built to help you understand and rehearse the method on your own practice sections, not to hand you homework or exam answers, and no tool can promise a particular mark or grade.

Where can I find past exam papers or practice for EGB375?

Start inside Queensland University of Technology's own systems: previous exam problems, tutorial questions and homework solutions are posted on the EGB375 Canvas site, and the free unit workbook is the primary practice source. This guide adds ten worked, exam-style design problems with fresh numbers so you can practise the same skills without reproducing any real paper; use Sia to check your reasoning on each step.

What can Sia do that a textbook can't?

A textbook shows one worked example and then stops; Sia responds to your specific working, so when your dn or your stress-block factor is off it can pinpoint the line and explain why, and it will re-explain a step as many times and as many ways as you need. It can generate a fresh practice section, walk the AS3600 check you are stuck on, and adapt to what you already know, all step by step and without ever promising an answer key or a grade.

Is EGB375 hard?

It is a design-calculation unit, so the challenge is procedural rather than abstract: you must apply the correct AS3600 factors and checks to each element and carry units cleanly, which rewards steady practice over memorisation. Students who build fluency with the flexure, shear and serviceability workflows and keep every calculation in N and mm tend to find it manageable.

Is the EGB375 exam open or closed book?

It is a closed-book, paper-based final scheduled by QUT Central Examinations, marked out of 100 and worth 50% of the unit. You may bring five A4 double-sided student-prepared note sheets, so it is not open-book and there is no official formula sheet; the duration is not stated in the unit materials, so confirm it on the QUT exam timetable.

What is examined in EGB375, and is there a hurdle?

The final is design-computation heavy: ultimate moment and shear capacity for reinforced and prestressed members, serviceability (cracking and deflection), slab, column and footing design, and reading shear-force and bending-moment diagrams, all to AS3600-2018. No hurdle is stated on any single component in the unit materials, but the 50% exam is the largest single piece of the mark, so confirm the current rules on Canvas and the unit outline.

What GPA do I need for a good grade in EGB375?

EGB375 is graded on GPA, Queensland University of Technology's 7-point grade-point average, and each grade maps to a band: grade 7 (High Distinction), grade 6 (Distinction), grade 5 (Credit) and grade 4 (Pass) - you need a 4 to pass. Your unit grade is built from the three assessment pieces (10% self-assessed homework reflection, 40% design project, 50% final exam), so a strong grade means scoring well on the design project and, above all, the 50% closed-book AS3600 final. Sia can help you target those bands compliantly: it explains each flexure, shear, serviceability, slab, column and footing workflow step by step so you build the fluency the exam rewards - it never guarantees a grade, and no tool can promise you a particular GPA.

How many credit points is EGB375 and what do I need to know first?

EGB375 is a 12-credit-point third-year civil-engineering unit at Queensland University of Technology. The unit materials do not list a specific prerequisite unit code, so treat the entry expectation as assumed knowledge rather than a named prerequisite: comfort with structural mechanics and analysis - drawing and reading shear-force and bending-moment diagrams for simply-supported and cantilever beams, and basic mechanics of materials - since EGB375 builds design methods on top of that (confirm the current prerequisites in the QUT unit outline). The unit runs on the Canvas LMS, where lectures, the free unit workbook, tutorial and homework problems and previous exam papers are posted. The closed-book final is scheduled in the QUT Central Examination period, with a revision/study week before it, so plan your final revision into that study week.

Study strategy

How to study for the exam

Treat EGB375 as a set of repeatable design workflows rather than a reading unit: for each element, learn the sequence once - recompute the stress-block factors, balance the forces (C = T or Cc + Cs = T), find the neutral axis, prove ductility (kuo <= 0.36), then apply phi and check adequacy - and practise it until it is automatic. Work every problem in newtons and millimetres and convert only at the end, because most lost marks are a wrong grade-dependent factor, a skipped ductility check, a mis-picked phi, or an N.mm to kN.m slip. Because the final is closed-book with five A4 double-sided note sheets, build those sheets as you revise: put the factors, one solved example per element (flexure, shear, serviceability, slab, column, footing) and the key AS3600 limits where you can find them fast, then rehearse the ten practice problems in this guide against the clock once you confirm the exam length on the QUT exam timetable. Use the QUT Central Examination period, with its revision/study week before the exam, as your dedicated window to consolidate those note sheets and work past exam papers and practice problems - the previous exam problems and tutorial and homework questions posted on Canvas are the best rehearsal for the real thing.

Study EGB375 with AI

Your AI Engineering tutor for EGB375

Stuck on a hard EGB375 question? Sia is AskSia’s AI Engineering tutor — ask any EGB375 Design of Concrete Structures question and get a clear, step-by-step explanation grounded in how the course is actually taught and assessed. Read this whole study guide free, then take your hardest questions to Sia.

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