Cambridge International as & A Level Physics (9702) · EXAM PREP

Unit 2 · Kinematics and Dynamics

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Unit 2 · Kinematics and Dynamics

— Kinematics and Dynamics
  • The Complete Cambridge International AS & A Level Physics (9702) Guide
  • Cambridge International AS & A Level Physics (9702)
  • 12 sections

Cambridge International does not publish a per-unit weighting for this exam. Exam structure (official): AS Level: Multiple Choice (75 min, 40 questions, 31%) · AS Level Structured Questions (75 min, 46%) · Advanced Practical Skills (120 min, 2 questions, 23%); A Level: Multiple Choice (75 min, 40 questions, 15.5%) · AS Level Structured Questions (75 min, 23%) · Advanced Practical Skills (120 min, 2 questions, 11.5%) · A Level Structured Questions (120 min, 38.5%) · Planning, Analysis And Evaluation (75 min, 2 questions, 11.5%). Be ready to carry the same unit skills and representations into a complete answer on every paper. Take the cart’s initial motion as positive before combining 1.20 m/s with an acceleration of 0.80 m/s². That convention gives meaning to both the calculated 4.80 m/s velocity and the 13.5 m displacement.

  • How Cambridge International AS & A Level Physics (9702) assesses this Cambridge International publishes no per-unit percentage for Cambridge International A Level Physics; Paper 1 accounts for 31% of the AS Level total and 15.5% of the A Level total. · AS Level: Multiple Choice (75 min, 40 questions, 31%) · AS Level Structured Questions (75 min, 46%) · Advanced Practical Skills (120 min, 2 questions, 23%) | A Level: Multiple Choice (75 min, 40 questions, 15.5%) · AS Level Structured Questions (75 min, 23%) · Advanced Practical Skills (120 min, 2 questions, 11.5%) · A Level Structured Questions (120 min, 38.5%) · Planning, Analysis And Evaluation (75 min, 2 questions, 11.5%) · show the model with A graph of velocity (m/s) against time (s)., A formula card that explains the pair of constant-acceleration equations separates final velocity from displacement., A table linking key concept, why it matters, visible method.
  • Key skills Motion Graphs and the Equations of Uniformly Accelerated Motion, Free Fall and Projectile Motion, Newton's Laws of Motion, Mass, Weight and Momentum, Non-uniform Motion: Friction, Drag and Terminal Velocity, Conservation of Linear Momentum: Elastic and Inelastic Collisions
  • How to study for Unit 2 This page turns A graph of velocity (m/s) against time (s)., A formula card that explains the pair of constant-acceleration equations separates final velocity from displacement., A table linking key concept, why it matters, visible method. into one route: Use v = u + at with the chosen positive direction.
  • The organizing decision Show how (m/s²) × s becomes m/s in the velocity line and how the extra factor of time produces meters in the displacement line.
Cambridge International AS & A Level Physics (9702) · Unit 2 of 12
Exam weight

Cambridge International does not publish a per-unit weighting for this exam.

Official unit name and weighting: Cambridge International syllabus.

Kinematics and Dynamics

Connect the published share to the unit model

Take the cart’s initial motion as positive before combining 1.20 m/s with an acceleration of 0.80 m/s². That convention gives meaning to both the calculated 4.80 m/s velocity and the 13.5 m displacement.

The velocity equation supplies an ordinate on a velocity–time graph, whereas displacement comes from ut + ½at² or the area under that graph. Confusing an ordinate with an area changes the requested quantity.

A complete solution retains seconds through each product and ends with forward directions. The sign convention therefore remains visible from setup to interpretation.

For any motion problem, define the positive direction before selecting a graph operation or dynamical law. A graph ordinate, a gradient and an area represent different quantities, so name the operation before using a number. Construct the relation symbolically, substitute consistent SI values, and interpret the sign in words so that velocity, displacement, momentum and resultant force remain directionally consistent.

The decision that organizes this unit

Define the system and choose the route before calculating

Show how (m/s²) × s becomes m/s in the velocity line and how the extra factor of time produces meters in the displacement line.

First move

Use v = u + at with the chosen positive direction

Mechanism route and repair branches

Relationships to preserve

  • Velocity change: Acceleration acts for 4.50 s.
  • Displacement: A velocity–time area has unit meters.
  • Direction: Velocity and displacement are vectors.

Representations to read

  • A graph of velocity (m/s) against time (s).
  • A formula card that explains the pair of constant-acceleration equations separates final velocity from displacement.
  • A table linking key concept, why it matters, visible method.

Branches to reject

  • Using the final velocity as though it were constant for the whole interval
  • Using s = ut + ½at² for a velocity coordinate
  • Dropping the time unit
Key conceptWhy it mattersVisible method
Velocity changeAcceleration acts for 4.50 sUse v = u + at with the chosen positive direction
DisplacementA velocity–time area has unit metersEvaluate ut + ½at² rather than reading one ordinate
DirectionVelocity and displacement are vectorsAttach “forward” to 4.80 m/s and 13.5 m
Declared positive directionEvery later sign depends on this choice.Write the direction before using a motion equation.
Graph operationOrdinate, gradient and area answer different questions.Name the requested operation and its resulting unit.
Assessment

How Cambridge International AS & A Level Physics (9702) assesses Kinematics and Dynamics

What a complete response must make visible

Match the task to evidence that a reader can audit, then check the most likely reasoning failure before finalizing the response.

TaskEvidence to showHurdle
Motion Graphs and the Equations of Uniformly Accelerated Motionvelocity–time gradient; terminal velocity; linear momentumUsing the final velocity as though it were constant for the whole interval
Free Fall and Projectile Motionvelocity–time gradient; terminal velocity; linear momentumUsing s = ut + ½at² for a velocity coordinate
Newton's Laws of Motion, Mass, Weight and Momentumvelocity–time gradient; terminal velocity; linear momentumDropping the time unit
Non-uniform Motion: Friction, Drag and Terminal Velocityvelocity–time gradient; terminal velocity; linear momentumUsing the final velocity as though it were constant for the whole interval
Conservation of Linear Momentum: Elastic and Inelastic Collisionsvelocity–time gradient; terminal velocity; linear momentumUsing s = ut + ½at² for a velocity coordinate
Worked examples

Worked example: motion graphs, momentum and resultant force

Read each question as it appears on the exam paper, choose your answer, then tap it to see the feedback.

Practice 1: Uniformly accelerated motion

Q. Which result correctly follows the stated sign convention? Read the exam question below, choose one option, then tap it to check.
9702/22 · Question 2Paper 2 AS Level Structured Questions · 75 minutes

A cart accelerates uniformly in a straight line.

A laboratory cart starts at 1.20 m/s and accelerates uniformly at 0.80 m/s² for 4.50 s. Calculate its final velocity and displacement, taking the initial direction as positive.

[4]

Show all necessary working.

A. v = 4.80 m/s forward; s = 13.5 m forward.

✅ Correct! 😊 Correct. Both u and a are positive, and the time factors give the stated velocity and displacement.

B. v = 4.80 m/s forward; s = 21.6 m forward.

❌ Not quite 😭 The velocity is correct, but this uses vt as though the final velocity acted for the entire interval. The cart accelerates from a lower speed.

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C. v = 2.40 m/s forward; s = 13.5 m forward.

❌ Not quite 😭 The displacement is right, but the velocity calculation has not added the full at = 3.60 m/s change.

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D. v = −4.80 m/s; s = −13.5 m.

❌ Not quite 😭 This reverses the chosen positive direction. The stated velocity and acceleration both act in the initial forward direction.

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Full explanation
  • Step 1Take the initial direction as positive, so u = +1.20 m/s and a = +0.80 m/s².
  • Step 2Use v = u + at to obtain v = 4.80 m/s.
  • Step 3Use s = ut + ½at² = (1.20)(4.50) + ½(0.80)(4.50)².
  • Step 4Calculate s = 13.5 m and state both results as forward.
Answer. A. v = 4.80 m/s forward; s = 13.5 m forward.
Model solution. Take the initial direction as positive. v = u + at = 1.20 m/s + (0.80 m/s²)(4.50 s) = 4.80 m/s. s = ut + ½at² = (1.20)(4.50) + ½(0.80)(4.50)² = 13.5 m. Final velocity = 4.80 m/s forward; displacement = 13.5 m forward.
Mark scheme focus. Apply constant-acceleration equations consistently with the chosen positive direction.

Practice 2: Impulse and momentum

Q. Which route correctly links force, time and the trolley's final velocity? Read the exam question below, choose one option, then tap it to check.
9702/22 · Question 3Paper 2 AS Level Structured Questions · 75 minutes

A force acts on a trolley for a short time.

A resultant force of 6.0 N acts for 0.40 s on a 1.5 kg trolley initially at rest. Determine its final velocity.

[3]

Show all necessary working.

A. Use F/t = mv, giving v = 10 m/s.

❌ Not quite 😭 Force divided by time is not impulse. The change in momentum equals force multiplied by the time interval.

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B. Use Ft = Δp = mv, giving v = 1.6 m/s.

✅ Correct! 😊 Correct. The impulse is 2.4 N s, equal to the final momentum because the trolley starts at rest.

C. Use F = mv, giving v = 4.0 m/s.

❌ Not quite 😭 Force is not momentum; their units differ. The duration of the force must appear through impulse.

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D. Use Ft = ½mv², giving v = 1.79 m/s.

❌ Not quite 😭 Impulse changes momentum, not kinetic energy directly. Equating N s to joules is dimensionally incorrect.

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Full explanation
  • Step 1Calculate the impulse: Ft = (6.0 N)(0.40 s) = 2.4 N s.
  • Step 2Impulse equals change in momentum, Δp.
  • Step 3The trolley starts at rest, so its final momentum mv is 2.4 kg m/s.
  • Step 4Calculate v = 2.4/1.5 = 1.6 m/s.
Answer. B. Use Ft = Δp = mv, giving v = 1.6 m/s.
Model solution. Impulse = Ft = (6.0 N)(0.40 s) = 2.4 N s. Since the trolley starts at rest, Ft = Δp = mv. Therefore v = 2.4/1.5 = 1.6 m/s.
Mark scheme focus. Use impulse as change in momentum and include the initial momentum correctly.
Glossary

Key terms for Unit 2: Kinematics and Dynamics

Models, uses, and boundaries

Kinematics and Dynamics
The pair of constant-acceleration equations separates final velocity from displacement. Use this relationship when the pair of constant-acceleration equations separates final velocity from displacement..
Worked example: motion graphs, momentum and resultant force
Seconds cancel one power from acceleration in v and both powers in the displacement term. Use this relationship when seconds cancel one power from acceleration in v and both powers in the displacement term..
Kinematics and Dynamics: change one condition
Reading the line at 2.50 s and 3.75 s compares velocities, not traveled distances. Use this relationship when reading the line at 2.50 s and 3.75 s compares velocities, not traveled distances..
Kinematics and Dynamics: test proposed results
Candidate values should respect the positive direction and constant 0.80 m/s² gradient. Use this relationship when candidate values should respect the positive direction and constant 0.80 m/s² gradient..
FAQ

Cambridge International AS & A Level Physics (9702) Unit 2 FAQ

How much of Cambridge International AS & A Level Physics (9702) does Unit 2 carry?

Cambridge International does not publish a per-unit weighting for this exam.

What is the first move on a Kinematics and Dynamics problem?

Use v = u + at with the chosen positive direction

Which relationships should I preserve?

Velocity change: Acceleration acts for 4.50 s. Displacement: A velocity–time area has unit meters. Direction: Velocity and displacement are vectors.

Which representations should I practice?

Practice moving among A graph of velocity (m/s) against time (s)., A formula card that explains the pair of constant-acceleration equations separates final velocity from displacement., A table linking key concept, why it matters, visible method..

What error should I check before submitting an answer?

Check for Using the final velocity as though it were constant for the whole interval; Using s = ut + ½at² for a velocity coordinate; Dropping the time unit.

Evidence workshop

Continue from the free model into complete practice

The full unit guide continues with the chapter’s worked examples, figures, scoring tables, and answer checks.

  • Worked example: motion graphs, momentum and resultant force
  • Kinematics and Dynamics: change one condition
  • Kinematics and Dynamics: test proposed results
  • Check the worked-example evidence for Kinematics and Dynamics

Full unit practice. Open the complete guide for the full evidence workshop and synthesis.

Study strategy

How to study Cambridge International AS & A Level Physics (9702) Unit 2

Start with the organizing decision

Before solving, restate the decision in operational terms: Show how (m/s²) × s becomes m/s in the velocity line and how the extra factor of time produces meters in the displacement line.. Your first written move should be to Use v = u + at with the chosen positive direction.

Practice the same idea in several representations

Rotate through A graph of velocity (m/s) against time (s)., A formula card that explains the pair of constant-acceleration equations separates final velocity from displacement., A table linking key concept, why it matters, visible method.. Use each representation to practice Motion Graphs and the Equations of Uniformly Accelerated Motion, Free Fall and Projectile Motion, Newton's Laws of Motion, Mass, Weight and Momentum, Non-uniform Motion: Friction, Drag and Terminal Velocity, Conservation of Linear Momentum: Elastic and Inelastic Collisions, and explain what stays invariant when the surface form changes.

Turn each error into a repair check

After every attempt, audit the response for Using the final velocity as though it were constant for the whole interval; Using s = ut + ½at² for a velocity coordinate; Dropping the time unit. Then redo only the first step that made the reasoning diverge, keeping units, direction, and model conditions visible.

Confirm current course details in the official Cambridge International syllabus for the 2025-2027 administration.

Next

Where to go next

Return to the Cambridge International AS & A Level Physics (9702) to see every unit and plan your revision.

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