Cambridge International as & A Level Physics (9702) · EXAM PREP

Unit 8 · Thermal Physics

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Unit 8 · Thermal Physics

— Thermal Physics
  • The Complete Cambridge International AS & A Level Physics (9702) Guide
  • Cambridge International AS & A Level Physics (9702)
  • 12 sections

Cambridge International does not publish a per-unit weighting for this exam. Exam structure (official): AS Level: Multiple Choice (75 min, 40 questions, 31%) · AS Level Structured Questions (75 min, 46%) · Advanced Practical Skills (120 min, 2 questions, 23%); A Level: Multiple Choice (75 min, 40 questions, 15.5%) · AS Level Structured Questions (75 min, 23%) · Advanced Practical Skills (120 min, 2 questions, 11.5%) · A Level Structured Questions (120 min, 38.5%) · Planning, Analysis And Evaluation (75 min, 2 questions, 11.5%). Be ready to carry the same unit skills and representations into a complete answer on every paper. The gas state uses 1.10 × 10⁵ Pa, 2.40 × 10⁻³ m³ and 300 K. Absolute temperature is essential because pV = nRT is not a Celsius-scale relation.

  • How Cambridge International AS & A Level Physics (9702) assesses this Cambridge International publishes no per-unit percentage for Cambridge International A Level Physics; Paper 1 accounts for 31% of the AS Level total and 15.5% of the A Level total. · AS Level: Multiple Choice (75 min, 40 questions, 31%) · AS Level Structured Questions (75 min, 46%) · Advanced Practical Skills (120 min, 2 questions, 23%) | A Level: Multiple Choice (75 min, 40 questions, 15.5%) · AS Level Structured Questions (75 min, 23%) · Advanced Practical Skills (120 min, 2 questions, 11.5%) · A Level Structured Questions (120 min, 38.5%) · Planning, Analysis And Evaluation (75 min, 2 questions, 11.5%) · show the model with A graph of pressure (kPa) against temperature (K)., A formula card that explains the ideal-gas relation balances pressure–volume energy with amount times rt., A table linking key concept, why it matters, visible method.
  • Key skills Thermal Equilibrium and Temperature Scales (A Level), Specific Heat Capacity and Specific Latent Heat (A Level), The Mole and the Ideal Gas Equation of State (A Level), Kinetic Theory of Gases (A Level), Internal Energy and the First Law of Thermodynamics (A Level)
  • How to study for Unit 8 This page turns A graph of pressure (kPa) against temperature (K)., A formula card that explains the ideal-gas relation balances pressure–volume energy with amount times rt., A table linking key concept, why it matters, visible method. into one route: Set pV = nRT.
  • The organizing decision Track joules on both sides of pV = nRT so that their cancellation leaves the amount of gas in moles.
Cambridge International AS & A Level Physics (9702) · Unit 8 of 12
Exam weight

Cambridge International does not publish a per-unit weighting for this exam.

Official unit name and weighting: Cambridge International syllabus.

Thermal Physics

Connect the published share to the unit model

The gas state uses 1.10 × 10⁵ Pa, 2.40 × 10⁻³ m³ and 300 K. Absolute temperature is essential because pV = nRT is not a Celsius-scale relation.

The product pV equals 264 J, while RT equals 2493 J mol⁻¹. Their quotient gives 0.1059 mol before the final three-significant-figure statement.

A separate pressure–temperature plot holds the appropriate gas conditions fixed as shown by its equation. Reading its inverse curve requires attention to which quantity is placed on each axis.

Convert temperature to the required absolute scale before choosing an ideal-gas, kinetic, heating or first-law relation. Define the system and energy sign convention when heat or work is involved, then substitute compatible units. The numerical result should be followed by a statement of the process and the direction of energy transfer.

The decision that organizes this unit

Define the system and choose the route before calculating

Track joules on both sides of pV = nRT so that their cancellation leaves the amount of gas in moles.

First move

Set pV = nRT

Mechanism route and repair branches

Relationships to preserve

  • Gas state: Pressure, volume and temperature belong to one sample.
  • Temperature: The supplied value is 300 K.
  • Amount: 264 J is divided by 2493 J mol⁻¹.

Representations to read

  • A graph of pressure (kPa) against temperature (K).
  • A formula card that explains the ideal-gas relation balances pressure–volume energy with amount times rt.
  • A table linking key concept, why it matters, visible method.

Branches to reject

  • Substituting a Celsius value or omitting the volume prefix
  • Treating the curve as p directly proportional to T
  • Swapping temperature and pressure
Key conceptWhy it mattersVisible method
Gas statePressure, volume and temperature belong to one sampleSet pV = nRT
TemperatureThe supplied value is 300 KKeep the absolute scale in the denominator
Amount264 J is divided by 2493 J mol⁻¹Report n = 0.106 mol
Absolute scaleGas relations require absolute temperature.Convert temperature before substitution.
System and transferHeat, work and internal energy depend on the chosen system and sign convention.Define both before applying the first law.
Assessment

How Cambridge International AS & A Level Physics (9702) assesses Thermal Physics

What a complete response must make visible

Match the task to evidence that a reader can audit, then check the most likely reasoning failure before finalizing the response.

TaskEvidence to showHurdle
Thermal Equilibrium and Temperature Scales (A Level)absolute temperature; specific latent heat; internal energySubstituting a Celsius value or omitting the volume prefix
Specific Heat Capacity and Specific Latent Heat (A Level)absolute temperature; specific latent heat; internal energyTreating the curve as p directly proportional to T
The Mole and the Ideal Gas Equation of State (A Level)absolute temperature; specific latent heat; internal energySwapping temperature and pressure
Kinetic Theory of Gases (A Level)absolute temperature; specific latent heat; internal energySubstituting a Celsius value or omitting the volume prefix
Internal Energy and the First Law of Thermodynamics (A Level)absolute temperature; specific latent heat; internal energyTreating the curve as p directly proportional to T
Worked examples

Worked example: absolute temperature, ideal gases and energy transfer

Read each question as it appears on the exam paper, choose your answer, then tap it to see the feedback.

Practice 1: Amount of an ideal gas

Q. Which rearrangement and dimensional check give the correct amount? Read the exam question below, choose one option, then tap it to check.
9702/42 · Question 1Paper 4 A Level Structured Questions · 120 minutes

A sealed sample behaves as an ideal gas.

An ideal-gas sample has pressure 1.10 × 10⁵ Pa, volume 2.40 × 10⁻³ m³ and temperature 300 K. Using R = 8.31 J mol⁻¹ K⁻¹, calculate the amount of gas.

[3]

Show all necessary working.

A. n = pV/(RT) = 0.106 mol.

✅ Correct! 😊 Correct. pV and RT have compatible joule-based units, leaving the amount in moles.

B. n = RT/(pV) = 9.44 mol.

❌ Not quite 😭 This inverts the ideal-gas rearrangement. From pV = nRT, the amount is pV divided by RT.

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C. n = pVT/R = 9.53 × 10³ mol.

❌ Not quite 😭 Temperature is placed in the numerator instead of the denominator. The expression also fails the intended dimensional cancellation.

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D. n = p/(VRT) = 1.84 × 10⁴ mol.

❌ Not quite 😭 This divides by volume even though pV forms the energy term in the ideal-gas equation. It is not the required rearrangement.

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Full explanation
  • Step 1Start from pV = nRT and rearrange to n = pV/(RT).
  • Step 2Calculate pV = (1.10 × 10⁵)(2.40 × 10⁻³) = 264 J.
  • Step 3Calculate RT = (8.31)(300) = 2493 J mol⁻¹.
  • Step 4Hence n = 264/2493 = 0.1059 mol ≈ 0.106 mol.
Answer. A. n = pV/(RT) = 0.106 mol.
Model solution. Using pV = nRT, n = pV/(RT) = (1.10 × 10⁵ Pa)(2.40 × 10⁻³ m³)/[(8.31 J mol⁻¹ K⁻¹)(300 K)]. Thus n = 264 J/2493 J mol⁻¹ = 0.1059 mol = 0.106 mol to three significant figures.
Mark scheme focus. Rearrange pV = nRT correctly and preserve compatible SI units through substitution.

Practice 2: Energy during a change of state

Q. Which method applies while the temperature remains constant? Read the exam question below, choose one option, then tap it to check.
9702/22 · Question 6Paper 2 AS Level Structured Questions · 75 minutes

A solid melts at constant temperature.

A 0.20 kg solid has specific latent heat of fusion 3.0 × 10⁵ J/kg. Calculate the energy needed to melt it completely.

[3]

Show all necessary working.

A. Use Q = mL to obtain 6.0 × 10⁴ J.

✅ Correct! 😊 Correct. Latent heat changes the state without a temperature change, so mass is multiplied by specific latent heat.

B. Use Q = mcΔT, taking ΔT = 0, to obtain 0 J.

❌ Not quite 😭 The temperature is constant, but energy is still required for the phase change. The specific latent heat relation is needed.

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C. Use Q = L/m to obtain 1.5 × 10⁶ J.

❌ Not quite 😭 Specific latent heat is energy per kilogram, so total energy is mL, not L divided by mass.

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D. Use Q = m/L to obtain 6.7 × 10⁻⁷ J.

❌ Not quite 😭 This rearrangement has incorrect dimensions for energy. Multiplying kg by J/kg is what leaves joules.

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Full explanation
  • Step 1A change of state at constant temperature uses specific latent heat, not a temperature-rise equation.
  • Step 2Use Q = mL.
  • Step 3Substitute Q = (0.20 kg)(3.0 × 10⁵ J/kg).
  • Step 4Calculate Q = 6.0 × 10⁴ J.
Answer. A. Use Q = mL to obtain 6.0 × 10⁴ J.
Model solution. During melting the temperature remains constant, so Q = mL. Q = (0.20 kg)(3.0 × 10⁵ J/kg) = 6.0 × 10⁴ J. The energy needed is 6.0 × 10⁴ J.
Mark scheme focus. Distinguish latent energy from temperature change and use Q = mL with consistent units.
Glossary

Key terms for Unit 8: Thermal Physics

Models, uses, and boundaries

Thermal Physics
The ideal-gas relation balances pressure–volume energy with amount times RT. Use this relationship when the ideal-gas relation balances pressure–volume energy with amount times RT..
Worked example: absolute temperature, ideal gases and energy transfer
Rearranging pV = nRT isolates moles after the joule units cancel. Use this relationship when rearranging pV = nRT isolates moles after the joule units cancel..
Thermal Physics: change one condition
The plotted temperatures of 325 K and 362 K lead to different pressures on the inverse curve. Use this relationship when the plotted temperatures of 325 K and 362 K lead to different pressures on the inverse curve..
Thermal Physics: test proposed results
Any proposed gas amount must use kelvin and preserve the 10⁻³ volume conversion. Use this relationship when any proposed gas amount must use kelvin and preserve the 10⁻³ volume conversion..
FAQ

Cambridge International AS & A Level Physics (9702) Unit 8 FAQ

How much of Cambridge International AS & A Level Physics (9702) does Unit 8 carry?

Cambridge International does not publish a per-unit weighting for this exam.

What is the first move on a Thermal Physics problem?

Set pV = nRT

Which relationships should I preserve?

Gas state: Pressure, volume and temperature belong to one sample. Temperature: The supplied value is 300 K. Amount: 264 J is divided by 2493 J mol⁻¹.

Which representations should I practice?

Practice moving among A graph of pressure (kPa) against temperature (K)., A formula card that explains the ideal-gas relation balances pressure–volume energy with amount times rt., A table linking key concept, why it matters, visible method..

What error should I check before submitting an answer?

Check for Substituting a Celsius value or omitting the volume prefix; Treating the curve as p directly proportional to T; Swapping temperature and pressure.

Evidence workshop

Continue from the free model into complete practice

The full unit guide continues with the chapter’s worked examples, figures, scoring tables, and answer checks.

  • Worked example: absolute temperature, ideal gases and energy transfer
  • Thermal Physics: change one condition
  • Thermal Physics: test proposed results
  • Check the worked-example evidence for Thermal Physics

Full unit practice. Open the complete guide for the full evidence workshop and synthesis.

Study strategy

How to study Cambridge International AS & A Level Physics (9702) Unit 8

Start with the organizing decision

Before solving, restate the decision in operational terms: Track joules on both sides of pV = nRT so that their cancellation leaves the amount of gas in moles.. Your first written move should be to Set pV = nRT.

Practice the same idea in several representations

Rotate through A graph of pressure (kPa) against temperature (K)., A formula card that explains the ideal-gas relation balances pressure–volume energy with amount times rt., A table linking key concept, why it matters, visible method.. Use each representation to practice Thermal Equilibrium and Temperature Scales (A Level), Specific Heat Capacity and Specific Latent Heat (A Level), The Mole and the Ideal Gas Equation of State (A Level), Kinetic Theory of Gases (A Level), Internal Energy and the First Law of Thermodynamics (A Level), and explain what stays invariant when the surface form changes.

Turn each error into a repair check

After every attempt, audit the response for Substituting a Celsius value or omitting the volume prefix; Treating the curve as p directly proportional to T; Swapping temperature and pressure. Then redo only the first step that made the reasoning diverge, keeping units, direction, and model conditions visible.

Confirm current course details in the official Cambridge International syllabus for the 2025-2027 administration.

Next

Where to go next

Return to the Cambridge International AS & A Level Physics (9702) to see every unit and plan your revision.

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