Ap Calculus Bc · EXAM PREP

Unit 5 · Analytical Applications of Differentiation

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The Complete AP Calculus BC Guide · AP Calculus BC

Unit 5 · Analytical Applications of Differentiation

— Use derivative evidence to justify global and local behavior
  • The Complete AP Calculus BC Guide
  • AP Calculus BC
  • 10 sections

Unit 5: Analytical Applications of Differentiation accounts for 10–15% of AP Calculus BC multiple-choice content. Section I has 42 multiple-choice questions in 100 minutes and contributes 50% of the score. For Section II's 6 free-response questions in 90 minutes (50%), be ready to carry the same unit skills and representations into a complete solution. College Board assigns this unit 10–15% of AP Calculus BC multiple-choice content; use that range to plan review time, not to predict a fixed number of questions or a free-response allocation.

  • How AP Calculus BC assesses this 10–15% of the multiple-choice section · Section I: 42 MCQs in 100 min, 50% · Section II: 6 FRQs in 90 min, 50% · show the model with first-derivative sign chart, aligned graphs of f f' and f'', objective and constraint diagram
  • Key skills Apply MVT and EVT, Analyze monotonicity and concavity, Optimize under constraints
  • How to study for Unit 5 This page turns first-derivative sign chart, aligned graphs of f f' and f'', objective and constraint diagram into one route: build the candidate set and sign chart before naming a conclusion.
  • The organizing decision use derivative signs and theorem hypotheses to justify behavior extrema and approximation
AP Calculus BC · Unit 5 of 10
Exam weight

Unit 5: Analytical Applications of Differentiation accounts for 10–15% of AP Calculus BC multiple-choice content.

Official unit name and weighting: College Board course and exam description.

Use derivative evidence to justify global and local behavior

Connect the published share to the unit model

College Board assigns this unit 10–15% of AP Calculus BC multiple-choice content; use that range to plan review time, not to predict a fixed number of questions or a free-response allocation.

Unit map language to know: critical point, local extremum, absolute extremum, increasing interval, decreasing interval, concavity, inflection point, Mean Value Theorem, first derivative test, and second derivative test; each term is used on this page and defined again in Appendix B.

Name the target before reading a derivative graph: sign controls increase, change in sign controls extrema, and change in the derivative controls concavity.

The decision that organizes this unit

Define the system and choose the route before calculating

use derivative signs and theorem hypotheses to justify behavior extrema and approximation

First move

build the candidate set and sign chart before naming a conclusion

Mechanism route and repair branches

Relationships to preserve

  • Critical numbers are candidates rather than automatic extrema
  • A derivative sign change classifies local extrema
  • Closed-interval absolute extrema require endpoints and all interior candidates

Representations to read

  • first-derivative sign chart
  • aligned graphs of f f' and f''
  • objective and constraint diagram

Branches to reject

  • calling every stationary point an extremum
  • using a theorem without its continuity or differentiability conditions
  • ignoring endpoints in an absolute-extrema problem
Key conceptWhy it's hardWhat scores
ExtremaZeros alone do not classify behaviorShows a sign change or compares all closed-interval candidates
Mean Value TheoremThe secant slope is not automatically attainedStates continuity, differentiability, and solves f′(c)=secant slope
ConcavityThe sign of f′ and change in f′ answer different questionsUses f″ or monotonicity of f′
Assessment

How AP Calculus BC assesses Analytical Applications of Differentiation

What a complete response must make visible

Match the task to evidence that a reader can audit, then check the most likely reasoning failure before finalizing the response.

TaskEvidence to showHurdle
Apply MVT and EVTfirst-derivative sign chart; Critical numbers are candidates rather than automatic extremacalling every stationary point an extremum
Analyze monotonicity and concavityaligned graphs of f f' and f''; A derivative sign change classifies local extremausing a theorem without its continuity or differentiability conditions
Optimize under constraintsobjective and constraint diagram; Closed-interval absolute extrema require endpoints and all interior candidatesignoring endpoints in an absolute-extrema problem
Worked examples

Resolve the Analytical Applications of Differentiation evidence conflict

Read each question as it appears on the exam paper, choose your answer, then tap it to see the feedback.

Practice 1: Absolute extrema on a closed interval

Q. Which candidate-and-value comparison is sufficient for the absolute extrema? Read the exam question below, choose one option, then tap it to check.
SECTION I · MULTIPLE CHOICE · QUESTION 1

A differentiable function is defined on [−2,3], and a table gives f and f′ at the endpoints and critical points.

Which procedure correctly locates the absolute extrema of f on [−2,3]?

Select the best answer.

A. Compare f at −2, 3, and every valid interior critical point; choose the largest and smallest f-values.

✅ Correct! 😊 This is the closed-interval method: endpoints and all valid interior critical candidates are tested using function values.

B. Compare only the interior inputs where f′=0.

❌ Not quite 😭 This omits endpoints and any domain points where f′ does not exist, so the absolute extrema could be missed.

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C. Choose the inputs having the largest and smallest values of f′.

❌ Not quite 😭 Derivative values describe rates of change, not the heights that determine absolute extrema.

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D. Every critical point is automatically an absolute maximum or minimum.

❌ Not quite 😭 Critical points are candidates only; their function values must be compared with one another and with endpoint values.

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Full explanation
  • Step 1List both endpoints and every interior point where f′=0 or f′ does not exist.
  • Step 2Discard any input outside the function domain or the closed interval.
  • Step 3Compare f, not f′, at every remaining candidate.
  • Step 4The greatest and least values identify the absolute maximum and minimum and their locations.
Answer. A. Compare f at −2, 3, and every valid interior critical point; choose the largest and smallest f-values.
Model answer. The absolute maximum and minimum are the largest and smallest tabulated f-values among the endpoints and valid interior critical points; exact locations require the supplied table values.
Scoring guideline. Build the complete closed-interval candidate set and compare function values at every candidate.

Practice 2: Applying the Mean Value Theorem

Q. Which interior input satisfies the Mean Value Theorem conclusion? Read the exam question below, choose one option, then tap it to check.
SECTION I · MULTIPLE CHOICE · QUESTION 2

Let f(x)=x² on [1,3].

At which value c in (1,3) does f′(c) equal the average rate of change of f on [1,3]?

Select the best answer.

A. c=1

❌ Not quite 😭 The left endpoint is not in the required open interval, even though it is used to compute the secant slope.

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B. c=2

✅ Correct! 😊 The secant slope is 4 and f′(x)=2x, so f′(2)=4 at an interior point.

C. c=3

❌ Not quite 😭 The right endpoint is excluded from the theorem’s conclusion and also gives derivative 6 rather than 4.

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D. No such c exists

❌ Not quite 😭 The polynomial is continuous on [1,3] and differentiable on (1,3), so the theorem applies and the calculation finds c=2.

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Full explanation
  • Step 1The polynomial is continuous on [1,3] and differentiable on (1,3).
  • Step 2The endpoint secant slope is (9−1)/(3−1)=4.
  • Step 3Solve f′(c)=2c=4 to obtain c=2, which lies in (1,3).
Answer. B. c=2
Model solution. Because f is continuous on [1,3] and differentiable on (1,3), the Mean Value Theorem applies. The secant slope is 4, and f′(c)=2c, so c=2.
Scoring guideline. State the Mean Value Theorem hypotheses and match an interior derivative to the endpoint secant slope.
Glossary

Key terms for Unit 5: Analytical Applications of Differentiation

Models, uses, and boundaries

Identify Critical-Number Candidates
A critical number lies in the function domain where the derivative is zero or undefined Choose this formula when the prompt asks you to identify critical-number candidates and the function, domain, interval, or representation matches the symbols shown. A Identify Critical-Number Candidates solution must stop if it applies this relationship before checking its domain, interval, endpoint, sign, and stated notation conditions.
Classify Extrema from Derivative Signs
Derivative sign changes classify local maxima and minima Choose this formula when the prompt asks you to classify extrema from derivative signs and the function, domain, interval, or representation matches the symbols shown. A Classify Extrema from Derivative Signs solution must stop if it applies this relationship before checking its domain, interval, endpoint, sign, and stated notation conditions.
Optimize on a Closed Interval
Closed-interval absolute extrema occur among endpoints and interior critical candidates Choose this formula when the prompt asks you to optimize on a closed interval and the function, domain, interval, or representation matches the symbols shown. A Optimize on a Closed Interval solution must stop if it applies this relationship before checking its domain, interval, endpoint, sign, and stated notation conditions.
Apply the Mean Value Theorem
The Mean Value Theorem matches an interior tangent slope to the endpoint secant slope Choose this formula when the prompt asks you to apply the mean value theorem and the function, domain, interval, or representation matches the symbols shown. A Apply the Mean Value Theorem solution must stop if it applies this relationship before checking its domain, interval, endpoint, sign, and stated notation conditions.
FAQ

AP Calculus BC Unit 5 FAQ

How much of AP Calculus BC does Unit 5 carry?

Unit 5: Analytical Applications of Differentiation accounts for 10–15% of AP Calculus BC multiple-choice content.

What is the first move on a Analytical Applications of Differentiation problem?

build the candidate set and sign chart before naming a conclusion

Which relationships should I preserve?

Critical numbers are candidates rather than automatic extrema A derivative sign change classifies local extrema Closed-interval absolute extrema require endpoints and all interior candidates

Which representations should I practice?

Practice moving among first-derivative sign chart, aligned graphs of f f' and f'', objective and constraint diagram.

What error should I check before submitting an answer?

Check for calling every stationary point an extremum; using a theorem without its continuity or differentiability conditions; ignoring endpoints in an absolute-extrema problem.

Evidence workshop

Continue from the free model into complete practice

The full unit guide continues with the chapter’s worked examples, figures, scoring tables, and answer checks.

  • Run the full closed-interval candidate test
  • Match an instantaneous rate to the interval’s average rate
  • Read extrema, concavity, and signed change from f′

Full unit practice. Open the complete guide for the full evidence workshop and synthesis.

Study strategy

How to study AP Calculus BC Unit 5

Start with the organizing decision

Before solving, restate the decision in operational terms: use derivative signs and theorem hypotheses to justify behavior extrema and approximation. Your first written move should be to build the candidate set and sign chart before naming a conclusion.

Practice the same idea in several representations

Rotate through first-derivative sign chart, aligned graphs of f f' and f'', objective and constraint diagram. Use each representation to practice Apply MVT and EVT, Analyze monotonicity and concavity, Optimize under constraints, and explain what stays invariant when the surface form changes.

Turn each error into a repair check

After every attempt, audit the response for calling every stationary point an extremum; using a theorem without its continuity or differentiability conditions; ignoring endpoints in an absolute-extrema problem. Then redo only the first step that made the reasoning diverge, keeping units, direction, and model conditions visible.

Confirm current course details in the official College Board course and exam description for the May 2027 administration.

Next

Where to go next

Return to the AP Calculus BC to see every unit and plan your revision.

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