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MAST20029 · Engineering Mathematics

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Chapter 6 of 12 · MAST20029

Stokes' Theorem

Stokes' theorem relates the flux of the curl over an open surface to the circulation of the field around its boundary: ∬_S (∇×F)·n̂ dS = ∮_C F·dr, with the surface normal and the boundary orientation tied together by the right-hand rule. It lets you swap a hard surface integral for an easier boundary line integral (or vice versa), and it makes the conservative-field result (zero curl ⇒ zero circulation) transparent.

In this chapter

What this chapter covers

  • 011. The statement ∬_S (∇×F)·n̂ dS = ∮_C F·dr (open surface S, boundary curve C)
  • 022. Open surface vs closed: Stokes needs a boundary curve (Gauss needs closure)
  • 033. The right-hand rule linking the normal n̂ to the orientation of C
  • 044. Choosing the easier side: compute the curl flux OR the boundary circulation
  • 055. Replacing a complicated cap by any surface with the same boundary
  • 066. Parametrising the boundary curve C to evaluate ∮_C F·dr
  • 077. Link to conservative fields: curl F = 0 ⇒ circulation = 0 round any loop
  • 088. Keeping orientation consistent so the two sides have matching signs
Worked example · free

Circulation via Stokes' theorem

Q [7 marks]. Let F = (−y) i + (x) j + (z) k. Let C be the unit circle x² + y² = 1 in the plane z = 0, oriented anticlockwise, and let S be the disk it bounds with upward normal. Use Stokes' theorem to find ∮_C F·dr. (7 marks)
  • 3 marksCompute the curl: ∇×F has i-component ∂(z)/∂y − ∂(x)/∂z = 0, j-component −(∂(z)/∂x − ∂(−y)/∂z) = 0, and k-component ∂(x)/∂x − ∂(−y)/∂y = 1 − (−1) = 2. So ∇×F = 2 k.
  • 2 marksChoose the surface S = the flat disk with upward normal n̂ = k, consistent with the anticlockwise C by the right-hand rule. Then (∇×F)·n̂ = (2 k)·k = 2.
  • 1 markApply Stokes: ∮_C F·dr = ∬_S (∇×F)·n̂ dS = ∬_S 2 dS = 2 · area(disk) = 2 · π(1)² = 2π.
  • 1 markState the circulation: 2π.
∮_C F·dr = 2π. Stokes' theorem turns the boundary circulation into a flux of the curl, which here is the constant 2 over a disk of area π.
Sia tip — Check that the normal and the boundary orientation obey the right-hand rule (anticlockwise C in the z=0 plane pairs with the upward normal k). You may replace the cap by ANY surface with the same boundary — pick the flat disk to make (∇×F)·n̂ as simple as possible. If curl F were zero, the circulation would be zero.
Glossary

Key terms

Stokes' theorem
∬_S (∇×F)·n̂ dS = ∮_C F·dr: the flux of the curl through an open surface equals the circulation of F around its boundary curve C.
Open surface
A surface with a boundary edge (a disk, a hemisphere cap). Stokes' theorem applies to open surfaces; the boundary curve C is what the line integral runs over.
Boundary curve C
The edge ∂S of an open surface S. Its orientation must be compatible with the surface normal n̂ by the right-hand rule for Stokes' theorem to hold with the correct sign.
Right-hand rule
The orientation convention: curl the right hand's fingers in the direction of C and the thumb points along n̂. It ties the boundary direction to the surface normal so both sides of Stokes agree in sign.
Circulation ∮_C F·dr
The line integral of F around the closed boundary curve C, measuring net flow along the loop. Stokes equates it to the flux of the curl through any surface bounded by C.
Surface independence
Stokes lets you replace the given cap by any other surface with the same boundary curve, since both give the same curl flux — choose the simplest (often the flat disk).
FAQ

Stokes' Theorem FAQ

What is the difference between Stokes' theorem and Gauss' theorem?

Gauss relates a CLOSED surface's flux to a volume integral of the divergence; Stokes relates an OPEN surface's curl flux to a line integral around its boundary. Gauss needs no boundary curve (closed surface); Stokes needs one (open surface). Read whether the surface is closed to choose the right theorem.

How do I orient the boundary curve correctly?

Use the right-hand rule: if the normal n̂ points up out of the surface, the boundary C is traversed anticlockwise as seen from the normal side. Get this wrong and your two sides differ by a sign. Stating the chosen normal and the matching orientation earns marks and prevents sign errors.

Can I change the surface in a Stokes calculation?

Yes — that is one of its main uses. The curl flux is the same through any surface sharing the same boundary curve C, so replace a complicated cap with the simplest surface (often the flat disk) to make (∇×F)·n̂ easy. Just keep the boundary and orientation fixed.

How does Stokes relate to conservative fields?

If F is conservative then curl F = 0, so the left side of Stokes is zero and therefore the circulation ∮_C F·dr around any closed loop is zero. This is exactly the path-independence property from the conservative-fields chapter, viewed through Stokes' theorem.

Study strategy

Exam move

Decide first which side is easier: if the curl is simple, compute the curl flux over the surface; if the boundary is a simple curve, compute the circulation directly. Always state the surface normal and confirm the boundary orientation by the right-hand rule before evaluating, since a wrong orientation flips the sign. Exploit surface independence — replace an awkward cap by the flat disk with the same boundary — and remember that a conservative field gives zero circulation. Practise the curl computation (with its + − + sign pattern) and a clean boundary parametrisation, and name the theorem you use.

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