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BUSS1020 · Quantitative Business Analysis

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Chapter 3 of 11 · BUSS1020

Basic Probability

Basic Probability (Week 3, Berenson Ch 4) gives you the rules for reasoning about uncertainty. You distinguish the three approaches to probability (a priori, empirical, subjective), apply the addition and multiplication rules, work with conditional probability and independence, reverse conditional statements with Bayes' theorem, and count outcomes with permutations and combinations. Contingency tables, decision trees and Venn diagrams are the visual tools that make these calculations concrete in a business setting.

In this chapter

What this chapter covers

  • 01Three approaches: a priori, empirical, subjective
  • 02Sample space, simple vs joint events, complement P(A') = 1 − P(A)
  • 03General addition rule and mutually exclusive events
  • 04Conditional probability P(A | B) = P(A and B)/P(B)
  • 05Multiplication rule and statistical independence
  • 06Marginal probability via the law of total probability
  • 07Bayes' theorem for reversing conditionals
  • 08Counting rules: multiplication, permutations, combinations
Worked example · free

Contingency table — conditional probability and independence

Q [7 marks]. Of 400 online orders, 240 used express shipping and 160 used standard. Among express orders 60 were returned; among standard orders 20 were returned. Build the logic from a table and find: P(returned), P(returned | express), and decide whether 'returned' and 'express' are independent.
  • 2 marksSet up the joint counts: express & returned = 60, express & not = 180; standard & returned = 20, standard & not = 140. Total returned = 60 + 20 = 80.
  • 1 markMarginal probability P(returned) = 80/400 = 0.20.
  • 2 marksConditional probability P(returned | express) = P(returned and express)/P(express) = 60/240 = 0.25.
  • 1 markIndependence test: events are independent only if P(returned | express) = P(returned). Here 0.25 ≠ 0.20.
  • 1 markConclude: 'returned' and 'express' are NOT independent — express orders are more likely to be returned.
P(returned) = 0.20, P(returned | express) = 0.25, and because these differ the two events are not independent.
Sia tip — For independence, comparing P(A | B) with P(A) is faster than checking P(A and B) = P(A)P(B), and it lets you say in words WHICH way the dependence runs — examiners reward that interpretation.
Glossary

Key terms

Conditional probability
P(A | B) = P(A and B)/P(B), the probability of A given that B has occurred; it re-scales probabilities to the subset where B is true.
Statistical independence
Events A and B are independent if knowing one tells you nothing about the other, i.e. P(A | B) = P(A), equivalently P(A and B) = P(A)P(B).
Mutually exclusive events
Events that cannot occur together, so P(A and B) = 0; the addition rule then simplifies to P(A or B) = P(A) + P(B).
Bayes' theorem
A rule for reversing a conditional probability: P(Bⱼ | A) = P(A | Bⱼ)P(Bⱼ) / Σ P(A | Bᵢ)P(Bᵢ), combining prior probabilities with new evidence.
Permutation vs combination
A permutation ₙPₖ = n!/(n−k)! counts ordered arrangements; a combination ₙCₖ = n!/[k!(n−k)!] counts unordered selections — order matters for one, not the other.
FAQ

Basic Probability FAQ

How do I know whether to use a permutation or a combination?

Ask whether order matters. If rearranging the same items counts as a different outcome (a ranking, a sequence), use a permutation; if only the group of items matters (a committee, a sample), use a combination. Combinations are always smaller than the matching permutations.

When do I actually need Bayes' theorem?

When you know P(A | B) but the question asks for P(B | A) — the reversed conditional. Classic cases are screening or detection problems: you know the test's hit rate given a condition, and you want the chance of the condition given a positive test. A contingency table version handles many exam cases without the full formula.

Are mutually exclusive and independent the same thing?

No, and confusing them is a common error. Mutually exclusive means the events can't happen together (P(A and B) = 0); independent means one event doesn't affect the other's probability. In fact, two events with non-zero probabilities that are mutually exclusive are necessarily dependent.

What's the fastest way to handle a 2×2 problem?

Convert any percentages to counts in a contingency table with margins. Once the cells are filled, marginal, joint and conditional probabilities are just the right cell over the right total — no formula memorisation needed.

Study strategy

Exam move

Make the contingency table your default weapon: most exam probability questions can be turned into a 2×2 (or 2×3) table of counts, after which every probability is a ratio. Practise the four definitions side by side — marginal, joint, conditional, and the independence check — and write each in words. For counting, build the habit of asking 'order or no order?' before reaching for a formula. Reserve the full Bayes formula for problems where a table is awkward, and always interpret the reversed probability in plain business language.

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