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MATH1061 · Mathematics 1a

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Chapter 6 of 7 · MATH1061

Vectors

A vector is an ordered list of numbers — geometrically an arrow you can add, scale and measure — and it is the language of every later linear-algebra topic. The single most powerful tool is the dot product, u·v = ‖u‖‖v‖cosθ, which is one scalar that encodes the angle between two vectors, decides orthogonality (dot product zero), and produces the projection of one vector onto another. In ℝ³ the cross product u × v gives a vector perpendicular to both (right-hand rule) whose length is the area of the parallelogram they span. These combine into the geometry of lines and planes in ℝ³: a line is a point plus a direction (parametric form), a plane is a point plus a normal (normal form), and the dot/cross products deliver the distances and angles between them.

In this chapter

What this chapter covers

  • 01B4 Vector arithmetic, length and the parallelogram law
  • 02B5 The dot product, angle and orthogonality
  • 03B5 Projection of one vector onto another
  • 04B6 The cross product in ℝ³ — the right-hand rule, parallelogram area
  • 05B7 Lines in ℝ³ — vector / parametric form
  • 06B7 Planes in ℝ³ — normal form, distances and angles
Worked example · free

Worked example: angle and cross product in ℝ³

Q [6 marks]. Let u = (1, 2, 2) and v = (2, 0, −1). (a) Find the angle between u and v. (b) Find a vector perpendicular to both.
  • +1(a) Dot product: u·v = (1)(2) + (2)(0) + (2)(−1) = 2 + 0 − 2 = 0.
  • +1(a) Interpret: u·v = 0 means the vectors are orthogonal — the angle is exactly 90°.
  • +1(a) Confirm via the formula: cosθ = u·v / (‖u‖‖v‖) = 0 / (3·√5) = 0, so θ = 90°.
  • +1(b) Set up the cross product: a vector perpendicular to both is u × v.
  • +1(b) Compute: u × v = (2·(−1) − 2·0, 2·2 − 1·(−1), 1·0 − 2·2) = (−2, 5, −4).
  • +1(b) Check: (−2, 5, −4)·u = −2 + 10 − 8 = 0 and ·v = −4 + 0 + 4 = 0 — perpendicular to both, as required.
(a) 90° — the dot product is 0, so u and v are orthogonal. (b) u × v = (−2, 5, −4), which the dot-product check confirms is perpendicular to both u and v.
Glossary

Key terms

Dot (scalar) product
u·v = u₁v₁ + u₂v₂ + u₃v₃ = ‖u‖‖v‖cos θ — a single number encoding the angle. Zero dot product means the vectors are orthogonal (perpendicular).
Norm (length)
‖u‖ = √(u·u) = √(u₁² + u₂² + u₃²), the length of the vector. A unit vector has norm 1; dividing a vector by its norm normalises it.
Projection
The projection of v onto u is (u·v / ‖u‖²) u — the shadow of v in u's direction. It splits v into a component along u and a component perpendicular to u.
Cross product
In ℝ³, u × v is the vector perpendicular to both u and v (direction by the right-hand rule) with length ‖u‖‖v‖sin θ = the area of the parallelogram they span. It is zero exactly when u and v are parallel.
Plane (normal form)
A plane in ℝ³ is fixed by a point and a normal vector n: every point r on it satisfies n·(r − r₀) = 0, i.e. n·r = d. The normal's components are the coefficients of x, y, z in the Cartesian equation.
FAQ

Vectors FAQ

What does the dot product tell me?

Three things at once. Its sign and value, via u·v = ‖u‖‖v‖cos θ, give the angle between the vectors. A dot product of exactly zero means they're orthogonal (perpendicular). And the dot product drives the projection formula. Whenever a question asks about an angle, perpendicularity, or a shadow/component, reach for the dot product first.

When do I use the cross product instead of the dot product?

Use the cross product when you need a vector perpendicular to two others (a normal to a plane), or an area/volume. It exists only in ℝ³ and returns a vector; the dot product works in any dimension and returns a scalar. Mnemonic: dot → angle/scalar, cross → perpendicular vector/area.

How do I write the equation of a line versus a plane in ℝ³?

A line needs a point and a direction vector: r = r₀ + t·d (parametric form). A plane needs a point and a normal vector: n·(r − r₀) = 0, which expands to the Cartesian ax + by + cz = d where (a, b, c) is the normal. The recurring move is finding the right normal — often via a cross product of two vectors lying in the plane.

How do I find the distance from a point to a plane?

Take the vector from any point on the plane to the external point, then project it onto the unit normal: the distance is |n·(p − r₀)| / ‖n‖. The dot product with the normalised normal extracts exactly the perpendicular component, which is the shortest distance.

Study strategy

Exam move

Make the dot product your default tool: it answers angle, orthogonality and projection questions in one formula, so compute u·v early and read off what the question needs. Reserve the cross product for ℝ³ perpendicular-vector, normal and area problems, and always verify your result with a dot-product check (it must be 0 against both inputs). For lines and planes, fix the form first — point + direction for a line, point + normal for a plane — then translate to parametric or Cartesian. Keep components and surds exact, and draw a quick sketch for sign and right-hand-rule sanity. Method marks come from showing the formula, not just the final number.

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