Ib Mathematics: Analysis and Approaches · EXAM PREP

Unit 5 · Topic 5: Calculus

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The Complete IB Mathematics: Analysis and Approaches Guide · IB Mathematics: Analysis and Approaches

Unit 5 · Topic 5: Calculus

— Rates, accumulation, and local approximation
  • The Complete IB Mathematics: Analysis and Approaches Guide
  • IB Mathematics: Analysis and Approaches
  • 5 sections

International Baccalaureate does not publish a per-unit weighting for this exam. Exam structure (official): SL: Paper 1 (90 min, 40%) · Paper 2 (90 min, 40%) · Internal Assessment (20%); HL: Paper 1 (120 min, 30%) · Paper 2 (120 min, 30%) · Paper 3 (60 min, 2 questions, 20%) · Internal Assessment (20%). Be ready to carry the same unit skills and representations into a complete answer on every paper. Differentiation measures local change, while integration measures signed accumulation. Stationary points require classification, geometric area may require splitting at roots, and an optimization result must be compared with feasible endpoints.

  • How IB Mathematics: Analysis and Approaches assesses this International Baccalaureate publishes no per-unit percentage for IB Mathematics: Analysis and Approaches; Paper 1 and Paper 2 each account for 40% of the SL total and 30% of the HL total. · SL: Paper 1 (90 min, 40%) · Paper 2 (90 min, 40%) · Internal Assessment (20%) | HL: Paper 1 (120 min, 30%) · Paper 2 (120 min, 30%) · Paper 3 (60 min, 2 questions, 20%) · Internal Assessment (20%) · show the model with a function graph with stationary points and signed regions, a derivative, bounded integral, or differential equation, a local Maclaurin series with its first omitted order
  • Key skills Limits, the Derivative, and Rules of Differentiation, Tangents, Normals, Increasing and Decreasing Functions, Stationary Points, and Inflexion, Optimization and Kinematics, Antiderivatives and Integration by Inspection and Substitution, Definite Integrals and Areas Under and Between Curves, Continuity, L'Hôpital's Rule, Implicit Differentiation, and Related Rates (HL), Further Integration: Substitution, By Parts, Partial Fractions, and Volumes of Revolution (HL), Differential Equations and Maclaurin Series (HL)
  • How to study for Unit 5 This page turns a function graph with stationary points and signed regions, a derivative, bounded integral, or differential equation, a local Maclaurin series with its first omitted order into one route: Write the relevant derivative, integral bounds, feasible interval, initial condition, or requested series order..
  • The organizing decision Decide whether the task concerns local change, signed accumulation, optimization, a rate model, or a local series before choosing a calculus method.
IB Mathematics: Analysis and Approaches · Unit 5 of 5
Exam weight

International Baccalaureate does not publish a per-unit weighting for this exam.

Official unit name and weighting: IB subject guide / subject brief.

Rates, accumulation, and local approximation

Connect the published share to the unit model

Differentiation measures local change, while integration measures signed accumulation. Stationary points require classification, geometric area may require splitting at roots, and an optimization result must be compared with feasible endpoints.

Kinematics links displacement, velocity, and acceleration by differentiation and integration. Integration technique is diagnosed from structure; differential equations retain equilibrium solutions and use initial conditions to select one curve.

A Maclaurin series describes local behavior near zero and must retain enough terms for the requested coefficient, approximation, or limit. Numerical results still need bounds, precision, and interpretation.

The decision that organizes this unit

Define the system and choose the route before calculating

Decide whether the task concerns local change, signed accumulation, optimization, a rate model, or a local series before choosing a calculus method.

First move

Write the relevant derivative, integral bounds, feasible interval, initial condition, or requested series order.

Mechanism route and repair branches

Relationships to preserve

  • A derivative describes local change, while a definite integral describes signed accumulation.
  • A stationary point needs a sign or second-derivative test before it can be classified.
  • An initial condition selects one solution from a family of differential-equation solutions.

Representations to read

  • a function graph with stationary points and signed regions
  • a derivative, bounded integral, or differential equation
  • a local Maclaurin series with its first omitted order

Branches to reject

  • calling every point with zero derivative a maximum or minimum
  • changing a negative signed integral into geometric area without explanation
  • dropping an integration constant before applying the initial condition
Key conceptWhy it's hardWhat scores
Curve featuresA zero derivative does not name the featureFinds candidates and classifies with signs or a second derivative
Accumulation and modelsSigned change can differ from total areaShows bounds, technique, initial condition, and units
Series approximationCancellation can erase the first retained termsKeeps sufficient order and states local use
Assessment

How IB Mathematics: Analysis and Approaches assesses Topic 5: Calculus

What a complete response must make visible

Match the task to evidence that a reader can audit, then check the most likely reasoning failure before finalizing the response.

TaskEvidence to showHurdle
Limits, the Derivative, and Rules of Differentiationlimit; derivative; local slopecalling every point with zero derivative a maximum or minimum
Tangents, Normals, Increasing and Decreasing Functions, Stationary Points, and Inflexionstationary point; second derivative; inflexionchanging a negative signed integral into geometric area without explanation
Optimization and Kinematicsfeasible interval; global maximum; negative velocitydropping an integration constant before applying the initial condition
Antiderivatives and Integration by Inspection and Substitutionantiderivative; substitution; constant of integrationcalling every point with zero derivative a maximum or minimum
Definite Integrals and Areas Under and Between Curvesdefinite integral; signed area; integral boundschanging a negative signed integral into geometric area without explanation
Continuity, L'Hôpital's Rule, Implicit Differentiation, and Related Rates (HL)continuity; implicit differentiation; related ratedropping an integration constant before applying the initial condition
Further Integration: Substitution, By Parts, Partial Fractions, and Volumes of Revolution (HL)integration by parts; partial fractions; volume of revolutioncalling every point with zero derivative a maximum or minimum
Differential Equations and Maclaurin Series (HL)differential equation; initial condition; Maclaurin serieschanging a negative signed integral into geometric area without explanation
Worked examples

Classify a stationary point and find signed area

Read each question as it appears on the exam paper, choose your answer, then tap it to see the feedback.

Practice 1: Classify a stationary point and retain signed area

Q. Which answer uses the required tests and interprets the integral correctly? Read the exam question below, choose one option, then tap it to check.
Paper 1 · Question 1[Maximum mark: 7]

Let f(x)=x³−3x.

(a) Classify the stationary point at x=1 and give its coordinates. (b) Find the signed accumulation from x=0 to x=1.

Show your working.

A. Since f′(1)=0 and f″(1)=6>0, (1,−2) is a local minimum; ∫ from 0 to 1 of f(x) dx=−5/4.

✅ Correct! 😊 Correct. The second derivative classifies the stationary point, and the bounded integral keeps its negative sign as signed accumulation.

B. Since f′(1)=0, (1,−2) is a local maximum; the signed accumulation is 5/4.

❌ Not quite 😭 A zero first derivative does not determine the classification. The positive second derivative indicates a minimum, and taking an absolute value changes signed accumulation into geometric area.

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C. Since f″(1)=6, (1,6) is a local minimum; the signed accumulation is −5/4.

❌ Not quite 😭 The second derivative value is not the function's y-coordinate. Evaluating f(1) gives −2, so the stated point is wrong.

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D. Since f(1)=−2, (1,−2) is a local minimum; ∫ from 0 to 1 of f′(x) dx=−5/4.

❌ Not quite 😭 The function value alone does not classify the point. Integrating f′ gives net change in f, not the requested accumulation of f.

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Full explanation
  • Step 1Differentiate: f′(x)=3x²−3, so f′(1)=0 and x=1 is stationary.
  • Step 2Since f″(x)=6x and f″(1)=6>0, the point is a local minimum; f(1)=−2.
  • Step 3Evaluate ∫ from 0 to 1 of (x³−3x) dx=[x⁴/4−3x²/2] from 0 to 1=−5/4.
  • Step 4The integral is negative because it is signed accumulation, not geometric area.
Answer. A. Since f′(1)=0 and f″(1)=6>0, (1,−2) is a local minimum; ∫ from 0 to 1 of f(x) dx=−5/4.
Model solution. The stationary point (1,−2) is a local minimum, and the signed area is −5/4 square units.
Markscheme focus. Verify and classify the stationary point, give its coordinate, and evaluate the definite integral without discarding its sign.

Practice 2: Use an initial condition in a rate model

Q. Which route correctly uses the initial condition and the requested series order? Read the exam question below, choose one option, then tap it to check.
Paper 1 · Question 2[Maximum mark: 7]

A function y satisfies a separable differential equation.

(a) Solve dy/dx=3y given that y(0)=2. (b) Write the Maclaurin series for e³ˣ through the x² term.

Show your working.

State the first omitted order in the series.

A. Obtain y=Ae³ˣ, use y(0)=2 to get A=2, and write e³ˣ=1+3x+9x²/2 plus terms of order x³ and above.

✅ Correct! 😊 Correct. The integration constant is retained until the initial condition fixes it, and substituting 3x into the exponential series gives the stated coefficients.

B. Obtain y=e³ˣ+2 and write e³ˣ=1+3x+3x²/2 plus terms of order x³ and above.

❌ Not quite 😭 The constant multiplies the exponential solution rather than being added. The quadratic coefficient must contain (3x)², giving 9x²/2.

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C. Obtain y=2eˣ and write e³ˣ=1+3x+9x² plus terms of order x³ and above.

❌ Not quite 😭 The differential equation requires exponential rate 3, not 1. The factorial denominator 2! is also missing from the quadratic series term.

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D. Obtain y=Ae³ˣ and stop, because the initial condition is already represented by A; write only 1+3x.

❌ Not quite 😭 An undetermined A is a family, not the requested particular solution. Stopping before the x² term also fails the requested truncation order.

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Full explanation
  • Step 1Separate variables to obtain dy/y=3 dx, then integrate to get ln|y|=3x+C.
  • Step 2Write the solution as y=Ae³ˣ and apply y(0)=2, giving A=2 and y=2e³ˣ.
  • Step 3Substitute u=3x into eᵘ=1+u+u²/2!+higher-order terms.
  • Step 4Thus e³ˣ=1+3x+9x²/2 plus terms of order x³ and above.
Answer. A. Obtain y=Ae³ˣ, use y(0)=2 to get A=2, and write e³ˣ=1+3x+9x²/2 plus terms of order x³ and above.
Model solution. Separating gives dy/y=3 dx, so ln|y|=3x+C and y=Ae³ˣ. Since y(0)=2, A=2; therefore y=2e³ˣ. Also, e³ˣ=1+3x+(3x)²/2! plus terms of order x³ and above, so e³ˣ=1+3x+9x²/2 plus terms of order x³ and above.
Markscheme focus. Separate the equation, apply the initial condition to obtain a particular solution, and keep all series terms through the requested power.
Glossary

Key terms for Unit 5: Topic 5: Calculus

Models, uses, and boundaries

Curve derivative
The derivative of x cubed minus 3x is 3x squared minus 3. Use it to locate stationary points before classifying them.
Box volume
The box volume is x times 20 minus 2x times 12 minus 2x. Use it on the feasible interval from zero to 6 centimeters.
Integration by parts
Integration by parts equals u times v minus the integral of v times du. Use it when the integrand has a product whose factors simplify after differentiation and integration.
Separable rate equation
Separating the rate equation gives dy divided by y equals 2 dx. Use it before applying the initial condition to select the particular solution.
Local series
The Maclaurin series for e to the power 2x begins 1 plus 2x plus 2x squared plus four-thirds x cubed. Use it near zero through the requested cubic term.
FAQ

IB Mathematics: Analysis and Approaches Unit 5 FAQ

How much of IB Mathematics: Analysis and Approaches does Unit 5 carry?

International Baccalaureate does not publish a per-unit weighting for this exam.

What is the first move on a Topic 5: Calculus problem?

Write the relevant derivative, integral bounds, feasible interval, initial condition, or requested series order.

Which relationships should I preserve?

A derivative describes local change, while a definite integral describes signed accumulation. A stationary point needs a sign or second-derivative test before it can be classified. An initial condition selects one solution from a family of differential-equation solutions.

Which representations should I practice?

Practice moving among a function graph with stationary points and signed regions, a derivative, bounded integral, or differential equation, a local Maclaurin series with its first omitted order.

What error should I check before submitting an answer?

Check for calling every point with zero derivative a maximum or minimum; changing a negative signed integral into geometric area without explanation; dropping an integration constant before applying the initial condition.

Evidence workshop

Continue from the free model into complete practice

The full unit guide continues with the chapter’s worked examples, figures, scoring tables, and answer checks.

  • Classify a stationary point and find signed area
  • Optimize a box and interpret velocity
  • Integrate by parts with visible choices
  • Solve a rate equation and build a local series

Full unit practice. Open the complete guide for the full evidence workshop and synthesis.

Study strategy

How to study IB Mathematics: Analysis and Approaches Unit 5

Start with the organizing decision

Before solving, restate the decision in operational terms: Decide whether the task concerns local change, signed accumulation, optimization, a rate model, or a local series before choosing a calculus method.. Your first written move should be to Write the relevant derivative, integral bounds, feasible interval, initial condition, or requested series order..

Practice the same idea in several representations

Rotate through a function graph with stationary points and signed regions, a derivative, bounded integral, or differential equation, a local Maclaurin series with its first omitted order. Use each representation to practice Limits, the Derivative, and Rules of Differentiation, Tangents, Normals, Increasing and Decreasing Functions, Stationary Points, and Inflexion, Optimization and Kinematics, Antiderivatives and Integration by Inspection and Substitution, Definite Integrals and Areas Under and Between Curves, Continuity, L'Hôpital's Rule, Implicit Differentiation, and Related Rates (HL), Further Integration: Substitution, By Parts, Partial Fractions, and Volumes of Revolution (HL), Differential Equations and Maclaurin Series (HL), and explain what stays invariant when the surface form changes.

Turn each error into a repair check

After every attempt, audit the response for calling every point with zero derivative a maximum or minimum; changing a negative signed integral into geometric area without explanation; dropping an integration constant before applying the initial condition. Then redo only the first step that made the reasoning diverge, keeping units, direction, and model conditions visible.

Confirm current course details in the official IB subject guide / subject brief for the 2027 administration.

Next

Where to go next

Return to the IB Mathematics: Analysis and Approaches to see every unit and plan your revision.

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