Ib Mathematics: Analysis and Approaches · EXAM PREP

Unit 1 · Topic 1: Number and Algebra

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The Complete IB Mathematics: Analysis and Approaches Guide · IB Mathematics: Analysis and Approaches

Unit 1 · Topic 1: Number and Algebra

— Patterns, exact forms, and proof
  • The Complete IB Mathematics: Analysis and Approaches Guide
  • IB Mathematics: Analysis and Approaches
  • 5 sections

International Baccalaureate does not publish a per-unit weighting for this exam. Exam structure (official): SL: Paper 1 (90 min, 40%) · Paper 2 (90 min, 40%) · Internal Assessment (20%); HL: Paper 1 (120 min, 30%) · Paper 2 (120 min, 30%) · Paper 3 (60 min, 2 questions, 20%) · Internal Assessment (20%). Be ready to carry the same unit skills and representations into a complete answer on every paper. Sequences, binomial coefficients, logarithms, complex numbers, and proof all reward a visible chain of exact statements. Arithmetic sequence and geometric sequence describe different recurrences; convergence belongs only to a geometric series whose ratio has magnitude below one.

  • How IB Mathematics: Analysis and Approaches assesses this International Baccalaureate publishes no per-unit percentage for IB Mathematics: Analysis and Approaches; Paper 1 and Paper 2 each account for 40% of the SL total and 30% of the HL total. · SL: Paper 1 (90 min, 40%) · Paper 2 (90 min, 40%) · Internal Assessment (20%) | HL: Paper 1 (120 min, 30%) · Paper 2 (120 min, 30%) · Paper 3 (60 min, 2 questions, 20%) · Internal Assessment (20%) · show the model with a term rule or finite-sum expression, an exact algebraic statement with its domain, a complex number in Cartesian or polar form
  • Key skills Arithmetic and Geometric Sequences and Series, Sigma Notation, and Financial Applications, Scientific Notation, Laws of Exponents and Logarithms, and Exponential Equations, The Binomial Theorem for Natural-Number Powers, Simple Deductive Proof and Identities, Counting Principles, Permutations and Combinations, and the Extended Binomial Theorem (HL), Partial Fractions and Systems of Linear Equations (HL), Complex Numbers: Cartesian, Polar and Euler Forms, De Moivre's Theorem, and Roots (HL), Proof by Induction, Contradiction, and Counterexample (HL)
  • How to study for Unit 1 This page turns a term rule or finite-sum expression, an exact algebraic statement with its domain, a complex number in Cartesian or polar form into one route: Name the sequence, expansion, logarithmic form, complex representation, or proof method that matches the prompt..
  • The organizing decision Choose the exact algebraic structure before calculating, and keep the index, domain, or proof claim visible.
IB Mathematics: Analysis and Approaches · Unit 1 of 5
Exam weight

International Baccalaureate does not publish a per-unit weighting for this exam.

Official unit name and weighting: IB subject guide / subject brief.

Patterns, exact forms, and proof

Connect the published share to the unit model

Sequences, binomial coefficients, logarithms, complex numbers, and proof all reward a visible chain of exact statements. Arithmetic sequence and geometric sequence describe different recurrences; convergence belongs only to a geometric series whose ratio has magnitude below one.

A binomial expansion begins with a general term, while an exponential equation begins with a domain and a choice of exact transformation. Complex number work uses modulus and argument, and polynomial proof uses factor, remainder, induction, contradiction, or a counterexample.

On a no-calculator paper, preserve exact form and show the law used. With a calculator, record the equation entered, the numerical result, and a domain or precision check.

The decision that organizes this unit

Define the system and choose the route before calculating

Choose the exact algebraic structure before calculating, and keep the index, domain, or proof claim visible.

First move

Name the sequence, expansion, logarithmic form, complex representation, or proof method that matches the prompt.

Mechanism route and repair branches

Relationships to preserve

  • Arithmetic sequences have a constant difference, while geometric sequences have a constant ratio.
  • A binomial coefficient follows from the selected power in the general term.
  • Complex roots share a modulus and are separated by equal changes in argument.

Representations to read

  • a term rule or finite-sum expression
  • an exact algebraic statement with its domain
  • a complex number in Cartesian or polar form

Branches to reject

  • using the term number as the exponent without checking the starting index
  • turning an exact result into a decimal too early
  • checking examples without completing the general proof
Key conceptWhy it's hardWhat scores
Sequence modelIndexing and convergence can be mixed upNames the model, term or sum rule, index, and units
Algebraic expansionThe requested power must be selected before arithmeticShows a general term and isolates the required exponent
Proof and complex formA numerical pattern is not a general argumentStates every branch or closes the logical implication
Assessment

How IB Mathematics: Analysis and Approaches assesses Topic 1: Number and Algebra

What a complete response must make visible

Match the task to evidence that a reader can audit, then check the most likely reasoning failure before finalizing the response.

TaskEvidence to showHurdle
Arithmetic and Geometric Sequences and Series, Sigma Notation, and Financial Applicationsarithmetic sequence; geometric series; finite sumusing the term number as the exponent without checking the starting index
Scientific Notation, Laws of Exponents and Logarithms, and Exponential Equationsexponential equation; logarithm domain; exact formturning an exact result into a decimal too early
The Binomial Theorem for Natural-Number Powersgeneral binomial term; coefficient; requested powerchecking examples without completing the general proof
Simple Deductive Proof and Identitiesdeductive proof; identity; counterexampleusing the term number as the exponent without checking the starting index
Counting Principles, Permutations and Combinations, and the Extended Binomial Theorem (HL)counting principle; permutation; combinationturning an exact result into a decimal too early
Partial Fractions and Systems of Linear Equations (HL)partial fractions; linear system; exact algebrachecking examples without completing the general proof
Complex Numbers: Cartesian, Polar and Euler Forms, De Moivre's Theorem, and Roots (HL)modulus; argument; Cartesian formusing the term number as the exponent without checking the starting index
Proof by Induction, Contradiction, and Counterexample (HL)induction hypothesis; contradiction; quantified conclusionturning an exact result into a decimal too early
Worked examples

Model a geometric saving plan

Read each question as it appears on the exam paper, choose your answer, then tap it to see the feedback.

Practice 1: Use the correct geometric index and sum

Q. Which expressions correctly answer the two different parts? Read the exam question below, choose one option, then tap it to check.
Paper 1 · Question 1[Maximum mark: 6]

A student follows a monthly saving plan.

A student deposits $120 in month 1 and increases each later deposit by 5%. Find (a) the month-8 deposit and (b) the total deposited through month 8.

Show your working.

Give monetary answers to the nearest cent.

A. Month 8: 120(1.05)⁷; total: 120((1.05)⁸−1)/(1.05−1).

✅ Correct! 😊 Correct. The first expression is the eighth term because counting begins at exponent 0, and the second sums all eight geometric terms.

B. Month 8: 120(1.05)⁸; total: 120((1.05)⁷−1)/(1.05−1).

❌ Not quite 😭 Both indices are shifted. The eighth term uses exponent 7, while a total through month 8 contains eight terms.

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C. Month 8: 120+8(0.05); total: 8(120+0.05).

❌ Not quite 😭 A percentage increase creates a constant ratio, not a constant difference. These arithmetic expressions do not model the deposits.

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D. Month 8: 120(1.05)⁷; total: 8·120(1.05)⁷.

❌ Not quite 😭 The eighth-deposit expression is correct, but multiplying it by eight assumes every deposit equals the last one. The total needs the geometric-sum rule.

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Full explanation
  • Step 1The first term is 120 and each term is multiplied by 1.05, so the sequence is geometric.
  • Step 2The eighth term is 120(1.05)⁸⁻¹=120(1.05)⁷=168.852… .
  • Step 3The finite total is 120((1.05)⁸−1)/(1.05−1)=1145.892… .
  • Step 4To the nearest cent, the two answers are $168.85 and $1,145.89.
Answer. A. Month 8: 120(1.05)⁷; total: 120((1.05)⁸−1)/(1.05−1).
Model solution. The month-8 deposit is $168.85 and the total through month 8 is $1,145.89.
Markscheme focus. Identify the geometric ratio, show the term index, apply the finite-sum formula, and label each monetary result.

Practice 2: Select a binomial term and preserve logarithmic form

Q. Which first steps select the requested power and correctly reverse the logarithm? Read the exam question below, choose one option, then tap it to check.
Paper 1 · Question 2[Maximum mark: 6]

Answer both independent algebraic parts.

(a) Find the coefficient of x⁴ in (3+x)⁶. (b) Solve log₂y=6, stating the required domain condition.

Give exact answers.

Show your working.

A. Set k=4 in C(6,k)3⁶⁻ᵏxᵏ, and rewrite log₂y=6 as y=2⁶ with y>0.

✅ Correct! 😊 Correct. The chosen general term contains x⁴, and exponential form gives the positive solution y=64.

B. Set k=2 because 6−k=4, and rewrite log₂y=6 as y=12.

❌ Not quite 😭 The power of x is k, so k must be 4. A logarithm is reversed by exponentiation, not by multiplying its base and value.

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C. Set k=4 in C(6,k)3ᵏx⁶⁻ᵏ, and rewrite the logarithm as y=6².

❌ Not quite 😭 This general term assigns the powers to the wrong binomial terms. The base 2 must be raised to 6, rather than reversing those roles.

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D. Expand only the first four terms, and allow y=±64 because logarithms have positive and negative branches.

❌ Not quite 😭 The x⁴ term may not appear in a partial expansion that stops too early. For real logarithms the input y must be positive, so there is no negative branch.

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Full explanation
  • Step 1The general term in (3+x)⁶ is C(6,k)3⁶⁻ᵏxᵏ.
  • Step 2Set k=4: the coefficient is C(6,4)3²=15·9=135.
  • Step 3Rewrite log₂y=6 in exponential form as y=2⁶=64.
  • Step 4The logarithm requires y>0, and y=64 satisfies this condition.
Answer. A. Set k=4 in C(6,k)3⁶⁻ᵏxᵏ, and rewrite log₂y=6 as y=2⁶ with y>0.
Model solution. The general term is C(6,k)3⁶⁻ᵏxᵏ. For x⁴, k=4, so the coefficient is C(6,4)3²=15·9=135. Also, log₂y=6 is equivalent to y=2⁶=64. The domain condition y>0 is satisfied.
Markscheme focus. Write a general binomial term, select the requested exponent before calculating, and reverse a logarithm while checking its domain.
Glossary

Key terms for Unit 1: Topic 1: Number and Algebra

Models, uses, and boundaries

Geometric sequence model
The nth term of a geometric sequence is the first term multiplied by the common ratio raised to one less than n. Use it when consecutive terms change by a constant ratio.
Monthly deposit
The eighth deposit is 120 multiplied by 1.05 to the seventh power. Use it to calculate the month-eight term in the savings example.
Binomial coefficient
The required binomial coefficient is five choose three multiplied by two squared, which equals 40. Use it after selecting the term containing x cubed.
Complex cube roots
The three cube roots have modulus 2 and arguments separated by two pi over three. Use it to generate every root rather than only the positive real root.
Induction step
The next induction case equals the assumed case plus three times k times k plus one. Use it to show that the next expression remains divisible by three.
FAQ

IB Mathematics: Analysis and Approaches Unit 1 FAQ

How much of IB Mathematics: Analysis and Approaches does Unit 1 carry?

International Baccalaureate does not publish a per-unit weighting for this exam.

What is the first move on a Topic 1: Number and Algebra problem?

Name the sequence, expansion, logarithmic form, complex representation, or proof method that matches the prompt.

Which relationships should I preserve?

Arithmetic sequences have a constant difference, while geometric sequences have a constant ratio. A binomial coefficient follows from the selected power in the general term. Complex roots share a modulus and are separated by equal changes in argument.

Which representations should I practice?

Practice moving among a term rule or finite-sum expression, an exact algebraic statement with its domain, a complex number in Cartesian or polar form.

What error should I check before submitting an answer?

Check for using the term number as the exponent without checking the starting index; turning an exact result into a decimal too early; checking examples without completing the general proof.

Evidence workshop

Continue from the free model into complete practice

The full unit guide continues with the chapter’s worked examples, figures, scoring tables, and answer checks.

  • Model a geometric saving plan
  • Extract a coefficient, then solve a logarithm
  • Find all cube roots in the complex plane
  • Prove a polynomial divisibility claim

Full unit practice. Open the complete guide for the full evidence workshop and synthesis.

Study strategy

How to study IB Mathematics: Analysis and Approaches Unit 1

Start with the organizing decision

Before solving, restate the decision in operational terms: Choose the exact algebraic structure before calculating, and keep the index, domain, or proof claim visible.. Your first written move should be to Name the sequence, expansion, logarithmic form, complex representation, or proof method that matches the prompt..

Practice the same idea in several representations

Rotate through a term rule or finite-sum expression, an exact algebraic statement with its domain, a complex number in Cartesian or polar form. Use each representation to practice Arithmetic and Geometric Sequences and Series, Sigma Notation, and Financial Applications, Scientific Notation, Laws of Exponents and Logarithms, and Exponential Equations, The Binomial Theorem for Natural-Number Powers, Simple Deductive Proof and Identities, Counting Principles, Permutations and Combinations, and the Extended Binomial Theorem (HL), Partial Fractions and Systems of Linear Equations (HL), Complex Numbers: Cartesian, Polar and Euler Forms, De Moivre's Theorem, and Roots (HL), Proof by Induction, Contradiction, and Counterexample (HL), and explain what stays invariant when the surface form changes.

Turn each error into a repair check

After every attempt, audit the response for using the term number as the exponent without checking the starting index; turning an exact result into a decimal too early; checking examples without completing the general proof. Then redo only the first step that made the reasoning diverge, keeping units, direction, and model conditions visible.

Confirm current course details in the official IB subject guide / subject brief for the 2027 administration.

Next

Where to go next

Return to the IB Mathematics: Analysis and Approaches to see every unit and plan your revision.

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