Ib Mathematics: Analysis and Approaches · EXAM PREP

Unit 2 · Topic 2: Functions

- one exam, every section, every strategy
5 Sections13-page Guide
Our own words - no official Ib Mathematics: Analysis and Approaches materials
Built for the current Ib Mathematics: Analysis and Approaches format · kept up to date
The Complete IB Mathematics: Analysis and Approaches Guide · IB Mathematics: Analysis and Approaches

Unit 2 · Topic 2: Functions

— Representations, transformations, and valid inputs
  • The Complete IB Mathematics: Analysis and Approaches Guide
  • IB Mathematics: Analysis and Approaches
  • 5 sections

International Baccalaureate does not publish a per-unit weighting for this exam. Exam structure (official): SL: Paper 1 (90 min, 40%) · Paper 2 (90 min, 40%) · Internal Assessment (20%); HL: Paper 1 (120 min, 30%) · Paper 2 (120 min, 30%) · Paper 3 (60 min, 2 questions, 20%) · Internal Assessment (20%). Be ready to carry the same unit skills and representations into a complete answer on every paper. A function links inputs to single outputs; a composite function follows the inner rule first, while an inverse reverses the mapping only on a one-to-one domain. Rational function features come from numerator zeros, denominator zeros, and long-run behavior.

  • How IB Mathematics: Analysis and Approaches assesses this International Baccalaureate publishes no per-unit percentage for IB Mathematics: Analysis and Approaches; Paper 1 and Paper 2 each account for 40% of the SL total and 30% of the HL total. · SL: Paper 1 (90 min, 40%) · Paper 2 (90 min, 40%) · Internal Assessment (20%) | HL: Paper 1 (120 min, 30%) · Paper 2 (120 min, 30%) · Paper 3 (60 min, 2 questions, 20%) · Internal Assessment (20%) · show the model with a function rule with domain and range, a transformed graph with intercepts and asymptotes, an exact factorization or bounded numerical root
  • Key skills Straight Lines, Domain and Range, Graphs and Their Key Features, Composite, Identity, and Inverse Functions, Quadratic Functions, Equations, Inequalities, and the Discriminant, Rational, Exponential, and Logarithmic Functions and Solving Equations, Transformations of Graphs, Polynomial Functions, Factor and Remainder Theorems, Sum and Product of Roots (HL), Further Rational Functions, Odd and Even Functions, and Self-Inverse Functions (HL), Inequalities, Modulus Functions, and Further Graph Transformations (HL)
  • How to study for Unit 2 This page turns a function rule with domain and range, a transformed graph with intercepts and asymptotes, an exact factorization or bounded numerical root into one route: State the domain and decide whether algebra, a graph, composition, inversion, or a numerical solver is the clearest route..
  • The organizing decision Choose a representation that exposes the function's valid inputs, transformations, and key features.
IB Mathematics: Analysis and Approaches · Unit 2 of 5
Exam weight

International Baccalaureate does not publish a per-unit weighting for this exam.

Official unit name and weighting: IB subject guide / subject brief.

Representations, transformations, and valid inputs

Connect the published share to the unit model

A function links inputs to single outputs; a composite function follows the inner rule first, while an inverse reverses the mapping only on a one-to-one domain. Rational function features come from numerator zeros, denominator zeros, and long-run behavior.

A translation changes coordinates, a stretch changes distance from an axis, and an absolute value can reflect negative outputs. Modulus equation and modulus inequality work must preserve the distance interpretation and test interval boundaries.

Exact algebra is usually the clean route when factorization or inverse structure is visible. A graphic display calculator is useful for numerical intersections, but the setup, viewing region, and accepted root still belong in written work.

The decision that organizes this unit

Define the system and choose the route before calculating

Choose a representation that exposes the function's valid inputs, transformations, and key features.

First move

State the domain and decide whether algebra, a graph, composition, inversion, or a numerical solver is the clearest route.

Mechanism route and repair branches

Relationships to preserve

  • A composite function applies the inner function before the outer function.
  • An inverse reverses a one-to-one mapping on a stated domain.
  • Zeros, excluded inputs, and long-run behavior determine rational-function features.

Representations to read

  • a function rule with domain and range
  • a transformed graph with intercepts and asymptotes
  • an exact factorization or bounded numerical root

Branches to reject

  • treating inverse notation as a reciprocal
  • giving a solver value without a search interval or substitution check
  • forgetting that a domain restriction selects the inverse branch
Key conceptWhy it's hardWhat scores
Function featuresA graph can hide a hole or restricted inputStates domain, intercepts, asymptotes, and transformations
Composition and inverseOrder matters and inverse notation is not a reciprocalShows the inner substitution and verifies a reversed pair
Modulus and numerical rootsSquaring can add invalid candidatesSplits cases or checks solver roots in the original equation
Assessment

How IB Mathematics: Analysis and Approaches assesses Topic 2: Functions

What a complete response must make visible

Match the task to evidence that a reader can audit, then check the most likely reasoning failure before finalizing the response.

TaskEvidence to showHurdle
Straight Lines, Domain and Range, Graphs and Their Key Featuresdomain; range; intercepttreating inverse notation as a reciprocal
Composite, Identity, and Inverse Functionscomposite function; inverse function; restricted domaingiving a solver value without a search interval or substitution check
Quadratic Functions, Equations, Inequalities, and the Discriminantquadratic function; discriminant; factorizationforgetting that a domain restriction selects the inverse branch
Rational, Exponential, and Logarithmic Functions and Solving Equationsvertical asymptote; horizontal asymptote; numerical roottreating inverse notation as a reciprocal
Transformations of Graphstranslation; vertical stretch; reflectiongiving a solver value without a search interval or substitution check
Polynomial Functions, Factor and Remainder Theorems, Sum and Product of Roots (HL)polynomial; factor theorem; remainder theoremforgetting that a domain restriction selects the inverse branch
Further Rational Functions, Odd and Even Functions, and Self-Inverse Functions (HL)rational function; odd function; self-inverse functiontreating inverse notation as a reciprocal
Inequalities, Modulus Functions, and Further Graph Transformations (HL)modulus inequality; closed interval; boundary pointgiving a solver value without a search interval or substitution check
Worked examples

Transform and analyze a rational function

Read each question as it appears on the exam paper, choose your answer, then tap it to see the feedback.

Practice 1: Read rational-function features from algebra

Q. Which rewritten form leads to the correct features and transformation? Read the exam question below, choose one option, then tap it to check.
Paper 1 · Question 1[Maximum mark: 7]

Let f(x)=(x+1)/(x−2).

State (a) the vertical and horizontal asymptotes, (b) the intercepts, and (c) the transformation from y=1/x.

Show your working.

A. f(x)=1+3/(x−2), giving asymptotes x=2 and y=1, intercepts (−1,0) and (0,−1/2), and a right 2, vertical stretch 3, up 1 transformation.

✅ Correct! 😊 Correct. The transformed reciprocal form exposes both shifts and the stretch, while the numerator and f(0) give the intercepts.

B. f(x)=1−3/(x−2), giving asymptotes x=2 and y=1 and intercepts (1,0) and (0,1/2).

❌ Not quite 😭 The division sign is wrong: x+1=(x−2)+3. This error changes both intercepts and reflects the reciprocal term incorrectly.

Prep with Sia Agent

Free download for Mac and Windows. Choose your computer:

Mac (Apple silicon) · Mac (Intel) · Windows

C. f(x)=1+3/(x+2), giving asymptotes x=−2 and y=1 and a shift 2 units left.

❌ Not quite 😭 The original denominator is zero at x=2, not x=−2. Changing x−2 to x+2 changes the function rather than rewriting it.

Prep with Sia Agent

Free download for Mac and Windows. Choose your computer:

Mac (Apple silicon) · Mac (Intel) · Windows

D. The asymptotes are x=−1 and y=−1/2 because they are the x- and y-intercepts.

❌ Not quite 😭 Intercepts are points where the graph meets an axis; they are not asymptotes. The denominator and long-run value determine the two asymptotes.

Prep with Sia Agent

Free download for Mac and Windows. Choose your computer:

Mac (Apple silicon) · Mac (Intel) · Windows

Full explanation
  • Step 1Divide to rewrite (x+1)/(x−2)=1+3/(x−2).
  • Step 2The denominator gives vertical asymptote x=2, and the translated reciprocal tends to horizontal asymptote y=1.
  • Step 3The transformation is 2 units right, a vertical stretch by factor 3, then 1 unit up.
  • Step 4Set x+1=0 for (−1,0), and evaluate f(0)=−1/2 for (0,−1/2).
Answer. A. f(x)=1+3/(x−2), giving asymptotes x=2 and y=1, intercepts (−1,0) and (0,−1/2), and a right 2, vertical stretch 3, up 1 transformation.
Model solution. The asymptotes are x=2 and y=1; the intercepts are (−1,0) and (0,−1/2).
Markscheme focus. Connect the transformed form, denominator, numerator, and function value to the correct graph features.

Practice 2: Choose the correct inverse branch

Q. Which answer respects composition order and the restricted domain? Read the exam question below, choose one option, then tap it to check.
Paper 1 · Question 2[Maximum mark: 6]

Let h(x)=(x−2)² for x≥2, and let g(x)=x+1.

(a) Find (h∘g)(3). (b) Find h⁻¹, including its domain. (c) Verify the inverse using the value from part (a).

Show your working.

A. (h∘g)(3)=4; h⁻¹(y)=2+√y for y≥0; h⁻¹(4)=4 and h(4)=4.

✅ Correct! 😊 Correct. Applying g first gives 4, the restriction selects the nonnegative square-root branch, and the two values verify the reversed mapping.

B. (h∘g)(3)=2; h⁻¹(y)=2−√y for y≥0.

❌ Not quite 😭 This does not apply g before h and chooses outputs below 2. That branch contradicts the stated domain x≥2.

Prep with Sia Agent

Free download for Mac and Windows. Choose your computer:

Mac (Apple silicon) · Mac (Intel) · Windows

C. (h∘g)(3)=4; h⁻¹(y)=1/(y−2)² for y≠2.

❌ Not quite 😭 The composition value is right, but inverse notation does not mean reciprocal. The inverse must undo squaring on the restricted branch.

Prep with Sia Agent

Free download for Mac and Windows. Choose your computer:

Mac (Apple silicon) · Mac (Intel) · Windows

D. (h∘g)(3)=16; h⁻¹(y)=2±√y for y≥0.

❌ Not quite 😭 Here h is applied to 4 as (4−2)²=4, not 16. Keeping both square-root branches also prevents the inverse from being a function.

Prep with Sia Agent

Free download for Mac and Windows. Choose your computer:

Mac (Apple silicon) · Mac (Intel) · Windows

Full explanation
  • Step 1Apply the inner function first: g(3)=4, then h(4)=(4−2)²=4.
  • Step 2From y=(x−2)² and x≥2, take the nonnegative branch: x=2+√y.
  • Step 3The range of h is y≥0, so this is the domain of h⁻¹.
  • Step 4Check h⁻¹(4)=4 and h(4)=4, which reverses the mapped pair.
Answer. A. (h∘g)(3)=4; h⁻¹(y)=2+√y for y≥0; h⁻¹(4)=4 and h(4)=4.
Model solution. First, g(3)=4, so (h∘g)(3)=h(4)=(4−2)²=4. From y=(x−2)² with x≥2, x=2+√y. Therefore h⁻¹(y)=2+√y for y≥0. Finally, h⁻¹(4)=4 and h(4)=4, verifying the inverse at the value found.
Markscheme focus. Apply composition in the correct order, use the domain restriction to select one inverse branch, and verify the reversed mapping.
Glossary

Key terms for Unit 2: Topic 2: Functions

Models, uses, and boundaries

Rational features
The rational function can be written as 1 plus 3 divided by x minus 2. Use it to read the transformations and both asymptotes.
Restricted inverse
On the restricted domain, the inverse output is 1 plus the nonnegative square root of the input. Use it when the original quadratic is restricted to inputs at least 1.
Modulus distance
The distance of 2x minus 3 from zero is at most 5. Use it to convert the modulus inequality into one double inequality.
Numerical root
The numerical target is the real zero of x cubed minus x minus 1. Use it with a bounded interval and a substitution check.
Exact roots
The quadratic factors into x minus 2 times x minus 3. Use it when exact factorization is visible and technology is unnecessary.
FAQ

IB Mathematics: Analysis and Approaches Unit 2 FAQ

How much of IB Mathematics: Analysis and Approaches does Unit 2 carry?

International Baccalaureate does not publish a per-unit weighting for this exam.

What is the first move on a Topic 2: Functions problem?

State the domain and decide whether algebra, a graph, composition, inversion, or a numerical solver is the clearest route.

Which relationships should I preserve?

A composite function applies the inner function before the outer function. An inverse reverses a one-to-one mapping on a stated domain. Zeros, excluded inputs, and long-run behavior determine rational-function features.

Which representations should I practice?

Practice moving among a function rule with domain and range, a transformed graph with intercepts and asymptotes, an exact factorization or bounded numerical root.

What error should I check before submitting an answer?

Check for treating inverse notation as a reciprocal; giving a solver value without a search interval or substitution check; forgetting that a domain restriction selects the inverse branch.

Evidence workshop

Continue from the free model into complete practice

The full unit guide continues with the chapter’s worked examples, figures, scoring tables, and answer checks.

  • Transform and analyze a rational function
  • Compose a function and verify its inverse
  • Solve a modulus inequality as a distance
  • Choose an analytic or numerical root route

Full unit practice. Open the complete guide for the full evidence workshop and synthesis.

Study strategy

How to study IB Mathematics: Analysis and Approaches Unit 2

Start with the organizing decision

Before solving, restate the decision in operational terms: Choose a representation that exposes the function's valid inputs, transformations, and key features.. Your first written move should be to State the domain and decide whether algebra, a graph, composition, inversion, or a numerical solver is the clearest route..

Practice the same idea in several representations

Rotate through a function rule with domain and range, a transformed graph with intercepts and asymptotes, an exact factorization or bounded numerical root. Use each representation to practice Straight Lines, Domain and Range, Graphs and Their Key Features, Composite, Identity, and Inverse Functions, Quadratic Functions, Equations, Inequalities, and the Discriminant, Rational, Exponential, and Logarithmic Functions and Solving Equations, Transformations of Graphs, Polynomial Functions, Factor and Remainder Theorems, Sum and Product of Roots (HL), Further Rational Functions, Odd and Even Functions, and Self-Inverse Functions (HL), Inequalities, Modulus Functions, and Further Graph Transformations (HL), and explain what stays invariant when the surface form changes.

Turn each error into a repair check

After every attempt, audit the response for treating inverse notation as a reciprocal; giving a solver value without a search interval or substitution check; forgetting that a domain restriction selects the inverse branch. Then redo only the first step that made the reasoning diverge, keeping units, direction, and model conditions visible.

Confirm current course details in the official IB subject guide / subject brief for the 2027 administration.

Next

Where to go next

Return to the IB Mathematics: Analysis and Approaches to see every unit and plan your revision.

AskSia is not affiliated with or endorsed by the International Baccalaureate Organization. IB and International Baccalaureate are registered trademarks of the International Baccalaureate Organization.
A+Everything unlocked
Unlocks this guide + all 5 Ib Mathematics: Analysis and Approaches sections - and more exam prep guides across AskSia.
Sia - your Ib Mathematics: Analysis and Approaches prep tutor, unlimited, worked the way the exam marks it
The full 13-page guide + practice bank with worked solutions
Chrome extension - bring Sia to any practice question on the web
Bilingual EN / Chinese on every guide and every Sia answer
$0.99 Trial
30-day money-back · cancel in one tap · how it works
Ib Mathematics: Analysis and Approaches · Topic 2: Functions - independent study guide on the AskSia Library. More Ib Mathematics: Analysis and Approaches prep
Unlock the full Ib Mathematics: Analysis and Approaches guide + 5 Ib Mathematics: Analysis and Approaches sections
$0.99 Trial