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CHEM10007 · Fundamentals Of Chemistry

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Chapter 11 of 11 · CHEM10007

Organic Chemistry II: Alkenes, Alkynes & Aromatics

The final week extends organic structure to unsaturated and cyclic systems. You name cycloalkanes, handle geometrical (cis–trans) isomerism arising from restricted rotation, and study alkenes (sp2, π bonds, E/Z nomenclature) and alkynes (sp, triple bonds). You finish with polyenes (conjugation and colour) and benzene/arenes, with IR spectroscopy appearing lightly as a structure-identification tool.

In this chapter

What this chapter covers

  • 01Cycloalkanes: 'cyclo' nomenclature
  • 02Geometrical (cis–trans) isomerism in rings and across C=C double bonds
  • 03Restricted rotation about a C=C double bond as the cause of cis–trans isomerism
  • 04Alkenes CnH2n: sp2 bonding and the π bond in ethene; −ene nomenclature with lowest locants
  • 05E/Z isomerism assigned by CIP priorities on each sp2 carbon
  • 06Polyenes: conjugation and colour (e.g. carotenoids)
  • 07Alkynes: sp bonding and the triple bond in acetylene; −yne nomenclature
  • 08Benzene and arenes: delocalised structure and naming of substituted derivatives; characteristic IR absorptions (C=O ≈ 1700–1800 cm−1, O−H/N−H ≈ 3300–3500 cm−1)
Worked example · free

E/Z assignment and alkene naming

Q [4 marks]. Consider the alkene CH3−CH=CH−CH2CH3 drawn with the two larger groups on opposite sides of the double bond. Give its full IUPAC name including the E/Z descriptor, and explain why the cis/trans labels alone are sometimes ambiguous.
  • 1 mark — parent chain and locantThe longest chain through the double bond has 5 carbons with the C=C between C-2 and C-3, so the parent is pent-2-ene.
  • 1 mark — CIP priority on both carbonsOn each sp2 carbon, rank the two attached groups by CIP priority (the carbon chain outranks H on each end).
  • 1 mark — correct E/Z assignmentThe two higher-priority groups are on opposite sides of the double bond, so the descriptor is E.
  • 1 mark — name and cis/trans limitationFull name: (E)-pent-2-ene. The cis/trans system breaks down when a double-bond carbon carries two different non-hydrogen groups, because 'same/opposite side' is undefined — E/Z (by CIP priority) is unambiguous.
(E)-pent-2-ene; cis/trans labelling is ambiguous when a double-bond carbon bears two different substituents, which is why the priority-based E/Z system is preferred.
Sia tip — Assign E/Z by comparing the higher-priority group on each end of the double bond: higher priorities on opposite sides = E, on the same side = Z. Restricted rotation about C=C is what makes these distinct isomers.
Glossary

Key terms

Geometrical (cis–trans) isomerism
Stereoisomerism caused by restricted rotation about a C=C double bond (or within a ring), giving distinct same-side (cis) and opposite-side (trans) arrangements.
E/Z isomerism
An unambiguous descriptor for double-bond geometry: higher-CIP-priority groups on opposite sides = E (entgegen), on the same side = Z (zusammen).
Alkene
A hydrocarbon with a C=C double bond, formula CnH2n; the carbons are sp2 hybridised with one σ and one π bond between them.
Alkyne
A hydrocarbon with a C≡C triple bond; the carbons are sp hybridised, as in acetylene (ethyne), named with the −yne suffix.
Conjugation
Alternating single and double bonds in a polyene that delocalise π electrons, often shifting light absorption into the visible region and producing colour.
FAQ

Organic Chemistry II: Alkenes, Alkynes & Aromatics FAQ

When does cis–trans isomerism occur?

It occurs when there is restricted rotation — across a C=C double bond or within a ring — and each of the relevant carbons carries two different groups. Free rotation about single bonds (as in alkanes) prevents it.

Why is E/Z preferred over cis/trans?

Cis/trans works only when it is clear which groups are 'the same'. When a double-bond carbon bears two different non-hydrogen substituents, E/Z resolves the ambiguity by comparing CIP priorities on each carbon.

Why are conjugated polyenes often coloured?

Extended conjugation delocalises the π electrons and lowers the energy gap between the bonding and antibonding π levels, so the molecule absorbs visible light — as in the carotenoids responsible for orange and red pigments.

Study strategy

Exam move

Practise alkene and alkyne IUPAC naming with lowest locants, and drill E/Z assignment by always comparing CIP priorities on both ends of the double bond. Be ready to explain the cis/trans limitation in words, since it is a favourite short-answer point. Keep IR spectroscopy light but memorise the two flagged absorptions (C=O and O−H/N−H), as they support structure-identification questions that can appear in the mock and practice exams.

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