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CHEM10007 · Fundamentals Of Chemistry

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Chapter 5 of 11 · CHEM10007

Thermochemistry, Calorimetry & Hess's Law

Energy bookkeeping for chemical reactions. You define heat, work and enthalpy, classify reactions as exothermic (ΔH < 0) or endothermic (ΔH > 0), and use the first law ΔU = q + w. The measurable skills are calorimetry (q = mcΔT and q = CcalΔT, linking measured heat to moles reacted and hence ΔH per mole) and Hess's Law (combining step enthalpies because ΔH is a path-independent state function).

In this chapter

What this chapter covers

  • 01Kinetic vs potential energy; heat (q) vs temperature; work (w); system vs surroundings
  • 02Exothermic (ΔH < 0, heat released) vs endothermic (ΔH > 0, heat absorbed)
  • 03First law of thermodynamics: ΔU = q + w
  • 04Enthalpy change ΔH of reaction
  • 05Calorimetry: q = mcΔT for a solution and q = CcalΔT for a calorimeter
  • 06Specific heat of water = 4.18 J g−1 °C−1
  • 07Relating measured q to moles reacted to obtain ΔH per mole
  • 08Hess's Law: reverse (flip sign) and scale (× n) component reactions; standard enthalpies of formation
Worked example · free

Calorimetry — heat released raises water temperature

Q [4 marks]. Burning 0.0150 mol of propane releases 2220 kJ per mole. The heat is absorbed by 400 g of water initially at 20.0 °C. Calculate the final temperature of the water. (specific heat of water = 4.18 J g−1 °C−1)
  • 1 mark — heat from moles × molar enthalpyHeat released: q = 0.0150 mol × 2220 kJ mol−1 = 33.3 kJ = 3.33 × 104 J.
  • 1 mark — correct rearrangementRearrange q = mcΔT for ΔT: ΔT = q ÷ (mc) = 3.33 × 104 ÷ (400 × 4.18).
  • 1 mark — temperature changeΔT = 3.33 × 104 ÷ 1672 = 19.9 °C.
  • 1 mark — final temperature and sanity checkTfinal = 20.0 + 19.9 = 39.9 °C — a reasonable rise for combustion heating water.
The water rises by 19.9 °C to a final temperature of 39.9 °C.
Sia tip — Watch your energy units: convert kJ to J before combining with a specific heat in J g−1 °C−1. Use the magnitude of q (the water gains the heat the reaction releases).
Glossary

Key terms

Enthalpy (ΔH)
The heat exchanged by a reaction at constant pressure. Negative for exothermic reactions (heat released), positive for endothermic ones.
Specific heat capacity (c)
The energy needed to raise 1 g of a substance by 1 °C; for water, 4.18 J g−1 °C−1. Used in q = mcΔT.
Calorimetry
Measuring heat flow from a temperature change, using q = mcΔT for the solution or q = CcalΔT for the calorimeter, to find a reaction's ΔH.
Hess's Law
Because enthalpy is a state function, the ΔH of an overall reaction equals the sum of the ΔH values of any set of steps that add to it.
State function
A property (like enthalpy) whose value depends only on the current state, not the path taken — which is why Hess's Law works.
FAQ

Thermochemistry, Calorimetry & Hess's Law FAQ

What is the difference between heat and temperature?

Temperature measures the average kinetic energy of particles; heat (q) is the energy transferred because of a temperature difference. A small mass at high temperature can carry less heat than a large mass at lower temperature.

How do I use Hess's Law?

Manipulate the given reactions so they add up to the target equation: reverse a reaction (flip the sign of its ΔH) and scale it (multiply ΔH by the same factor). Sum the adjusted ΔH values to get the overall enthalpy change.

Why must I convert kJ to J in calorimetry?

The specific heat of water is given in J g−1 °C−1, so q in q = mcΔT comes out in joules. Mixing kJ and J is a common error that throws the temperature change off by a factor of 1000.

Study strategy

Exam move

Keep your sign convention straight: a reaction releasing heat (ΔH < 0) warms the surroundings, so the water gains that energy. Practise the two-way link between measured q and ΔH per mole, since the calorimetry archetype recurs and connects to the F4 thermodynamics practical. For Hess's Law, set up a clean table of reversed/scaled reactions and their ΔH so the bookkeeping is transparent and easy to mark.

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