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PSYB06H3 Chap.3 Probability Rules and Bayesian Reasoning

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Probability Rules and Bayesian Reasoning

Three operations behind every question

Probability problems in this course are assembled from three moves. A joint probability asks for two outcomes together, an additive probability asks for one outcome or another, and a conditional probability asks for an outcome once another is known.

Recognising which move a question wants is usually the hardest step; the arithmetic that follows is short.

Overlap and exclusivity

When two outcomes can happen together, adding their probabilities double counts the shared part, so the overlap is subtracted once. Outcomes that cannot co-occur are mutually exclusive and have nothing to subtract.

A set of outcomes that covers every possibility is exhaustive and sums to one, which makes it possible to find a probability by subtracting its complement from one.

Independence and the multiplicative rule

Two outcomes are independent when knowing one leaves the probability of the other unchanged. Only then does the joint probability equal the simple product of the two probabilities.

In general the joint probability multiplies the first probability by the conditional probability of the second, a rule that works whether or not the outcomes are independent.

Comparing a table cell with the product of its margins is a quick independence test, and a mismatch tells you to keep the conditional form of the rule for any later calculation.

Updating with evidence

Bayes' rule reverses a conditional probability. It combines how common a hypothesis is beforehand, how often the evidence appears when the hypothesis is true, and how often the evidence appears overall.

Screening problems show why this matters: when a condition is rare, most positive results can come from people without it. Converting the percentages into counts for an imagined population of 1000 keeps the reasoning concrete and every total checkable.

Empirical and analytical answers

An analytical probability counts qualifying outcomes against all possible outcomes, such as three odd faces out of six on a die.

An empirical probability comes from repeating the event and counting what happens. With few repetitions the two can disagree noticeably because of random noise, but with many repetitions the empirical value settles close to the analytical one, much as larger samples better represent a population.

When a situation is too complex to analyse directly, repeated observation or simulation becomes the only practical route to a probability.

In this chapter

What this chapter covers

  • 01

    Analytical and Empirical Probability

  • 02

    Joint Probability

  • 03

    Additive Rule and Overlap

  • 04

    Mutually Exclusive and Exhaustive Outcomes

  • 05

    Conditional Probability and Independence

  • 06

    Bayes' Rule and Contingency Tables

Worked example · free

Sleep and anxiety in a contingency table

Q [4 marks]. AskSia-authored practice. In a survey of 300 students, 120 report insomnia and 48 of those also report anxiety; 60 of the 180 without insomnia report anxiety. Find p(anxiety), p(insomnia and anxiety), p(insomnia or anxiety) and p(anxiety given insomnia), then decide whether the two reports are independent. The four marks are an AskSia practice allocation, not a University marking scheme.
Region probabilities for an AskSia student survey: 0.27 attend tutorials only, 0.18 do both, 0.12 use flashcards only and 0.43 do neither, so the four regions sRegion probabilities for an AskSia student survey: 0.27 attend tutorials only, 0.18 do both, 0.12 use flashcards only and 0.43 do neither, so the four regions sum to one.0.270.180.120.43TutorialsFlashcardsNeither
Region probabilities for an AskSia student survey: 0.27 attend tutorials only, 0.18 do both, 0.12 use flashcards only and 0.43 do neither, so the four regions sum to one.
  • 1Anxiety total: 48 + 60 = 108, so p(anxiety) = 108 / 300 = 0.36.
  • 1Joint: p(insomnia and anxiety) = 48 / 300 = 0.16.
  • 1Additive: 120/300 + 108/300 − 48/300 = 180/300 = 0.60.
  • 1Conditional: 48 / 120 = 0.40, which differs from 0.36, so the reports are not independent.
Anxiety is reported by 108 of the 300 students, a probability of 0.36. Insomnia with anxiety covers 48 students, or 0.16. Insomnia or anxiety adds the two totals and subtracts the shared 48 once, giving 180 / 300 = 0.60. Among students with insomnia, 48 of 120 report anxiety, so p(anxiety given insomnia) = 0.40. Because 0.40 is not equal to the overall 0.36, knowing about insomnia changes the probability of anxiety. The same conclusion follows from the product rule: 0.40 × 0.36 = 0.144, which is not the observed joint probability of 0.16.
Sia tip — For a conditional probability, circle the group named after the word given; its total is your denominator.
Glossary

Key terms

Joint Probability
The probability that two outcomes occur together, written p(A and B).
Additive Rule
The rule that p(A or B) equals p(A) plus p(B) minus their joint probability.
Mutually Exclusive Events
Outcomes that cannot occur together, so their joint probability is zero.
Exhaustive Set
A collection of outcomes that covers every possibility, so their probabilities sum to one.
Independence
The property that one outcome leaves the probability of another unchanged, so p(B given A) equals p(B).
Posterior Probability
The probability of a hypothesis after the evidence is taken into account, calculated with Bayes' rule.
FAQ

Probability Rules and Bayesian Reasoning FAQ

How can I tell an AND question from a GIVEN question?

An AND question treats both outcomes as unknown and asks how often they occur together, so it divides by everyone. A GIVEN question tells you one outcome has already happened, so it divides only by that group. Rewording the question as a fraction of a specific group usually reveals which one is meant.

Are mutually exclusive events independent?

No. If two outcomes cannot happen together, learning that one occurred drops the probability of the other to zero, which is a change. Independence requires the probability to stay the same. The two ideas are often confused because both make the arithmetic simpler in different ways.

Why does a positive screening result often mean a low chance of the condition?

When a condition is rare, the many people without it generate false positives that can outnumber the true positives from the few people with it. The probability of the condition after a positive result depends on how common it was to begin with, not only on how accurate the test is.

Does a long run of one outcome make the other outcome due?

Not for independent events such as tosses of a fair coin. Each toss keeps the same probability regardless of earlier results, so eight heads in a row still leave the next toss at a probability of 0.50. Expecting a correction treats separate trials as if they remembered one another.

Study strategy

Exam move

Build a two-by-two contingency table for an everyday example and compute every joint, marginal and conditional probability it contains. Check independence by comparing a cell with the product of its margins. Then rework a Bayes problem twice, once with probabilities and once with counts for 1000 people, and confirm both routes agree to four decimal places.

Write down which group is the denominator before each division, and finish by stating in words what the final probability describes.

Working through Probability Rules and Bayesian Reasoning in PSYB06H3? Sia is AskSia’s AI Statistics tutor — ask any PSYB06H3 Probability Rules and Bayesian Reasoning question and get a clear, step-by-step explanation grounded in how PSYB06H3 is taught and assessed. Read this chapter free, then take your hardest questions to Sia.

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