National University of Singapore · FACULTY OF BIOLOGY

LSM2106 Chap.8 Cellular Oxygenation

- one subject, every graph, every model, every mark
7 Chapters4-page Bible
Our own words - no uploaded lecturer files
Updated for this semester
Chapter 8 of 11 · LSM2106

Cellular Oxygenation

Why the binding curve has to be sigmoid

The eighth lecture covers cellular oxygenation. Oxygen dissolves poorly in water and is consumed continuously at the end of the respiratory chain, so dissolved gas alone cannot supply a tissue.

A carrier protein solves the problem only if it can do two contradictory things: hold oxygen tightly where it is plentiful and release it where it is scarce.

A single-site carrier binds by the same hyperbolic relation that describes an enzyme and its substrate, and it cannot escape the contradiction.

Positioned to be nearly saturated in the lungs it stays nearly saturated in the tissues; positioned to unload in the tissues it fails to load. The fraction released between two pressures is small wherever the curve is placed.

A cooperative carrier escapes, because binding at one subunit makes the remainder bind more readily and the curve becomes sigmoid: flat at low pressure, steep through a narrow band, flat again at high pressure. Placing the steep band between tissue and lung pressures gives near-complete loading at one end and substantial unloading at the other.

The quantity that matters is never the saturation at either point but the difference between them.

Three modulators that all report the same fact

A fixed curve would still be a poor design, because demand varies. Three signals move it, and all three rise in a tissue that is working.

Carbon dioxide hydrates and dissociates, lowering local pH, and the protons released bind to ionisable groups on the carrier and reduce its affinity. Carbon dioxide also binds the protein directly, with the same effect and independently of the pH change. An organic phosphate in red cells binds a cavity in the deoxygenated form and stabilises it, again reducing affinity.

The mechanism is a feedback loop written in chemistry rather than in signalling, and it depends on the pK reasoning of the earlier chapters: the effect exists only because the relevant side chains have pK values near the physiological range, so a small pH shift changes their protonation state.

Position on the curve decides how large any of this is.

A shift of a given size produces a large change in saturation on the steep central band and almost none on either plateau, which is why the modulators matter in a working tissue and not in the lungs. Once delivered, oxygen serves as the final acceptor of electrons stripped from fuel, and its absence stalls the whole chain rather than one reaction.

In this chapter

What this chapter covers

  • 01

    The transport problem posed by low solubility and continuous consumption

  • 02

    Hyperbolic binding and why it cannot both load and unload well

  • 03

    Sigmoid binding, and the delivered fraction as the quantity of interest

  • 04

    Falling pH, carbon dioxide and an organic phosphate as modulators

  • 05

    Ionisable groups with pK values near the working range

  • 06

    Position on the curve as the amplifier of any shift

  • 07

    Oxygen as terminal electron acceptor and the consequence of its absence

Worked example · free

How much oxygen is actually delivered

Q [6 marks]. A cooperative carrier is 98 per cent saturated at lung pressure and 60 per cent saturated at resting tissue pressure. During exercise the tissue pressure falls and local pH drops, leaving it 25 per cent saturated there. Compare the delivered fraction at rest and in exercise, and say which factor contributed more. The marks used here are ours as a study aid and are not an official University allocation.
  • 2Compute the delivered fraction in each condition.
  • 2Distinguish movement along the curve from a shift of the curve.
  • 2Explain why the second effect is amplified.
At rest the carrier gives up 98 minus 60, or 38 per cent of its capacity. In exercise it gives up 98 minus 25, or 73 per cent, close to double. Falling tissue pressure moves the working point along the existing curve, whereas falling pH shifts the whole curve to the right so that saturation is lower at every pressure. Because the resting point already lies on the steep central band, a modest rightward shift there produces a large change in saturation. The pH effect is therefore amplified by the shape of the curve rather than simply added to the pressure effect.
Sia tip — Always subtract two saturations rather than quoting one. A carrier that is 95 per cent saturated sounds efficient and may be delivering almost nothing, because delivery is a difference between two points and not a value at either.
Glossary

Key terms

Fractional saturation
The proportion of available binding sites on a carrier that are occupied at a stated partial pressure of the bound gas.
Sigmoid binding curve
An S-shaped saturation curve produced by cooperative binding, flat at both extremes and steep through an intermediate band.
Delivered fraction
The difference between saturation where the carrier loads and saturation where it unloads, which is the quantity that measures transport performance.
Affinity shift
A movement of the whole saturation curve along the pressure axis caused by a modulator, as distinct from movement of the working point along a fixed curve.
Terminal electron acceptor
The species that receives electrons at the end of the respiratory chain and is reduced in the process, allowing the carriers upstream to be re-oxidised.
FAQ

Cellular Oxygenation FAQ

Why is a cooperative carrier better than one with simple hyperbolic binding?

Because transport requires a large difference in saturation between two pressures, not high affinity in itself. A hyperbolic carrier gives a small difference wherever it is placed, since its curve changes gently everywhere. A sigmoid curve concentrates all its steepness into one band, so a carrier tuned to that band loads almost fully at one end and releases a large fraction at the other.

Does a falling pH help or hinder oxygen delivery?

It helps. Protons bind to the carrier and lower its affinity, shifting the curve to the right so that more oxygen is released at any given pressure. Since a working tissue produces carbon dioxide and therefore protons, the signal arrives exactly where the extra delivery is needed, which makes the mechanism self-regulating.

Why does the same pH change have almost no effect in the lungs?

Because the working point there sits on the upper plateau, where the curve is nearly flat. A shift along the pressure axis produces very little change in saturation on a flat region. The size of any modulator effect depends on where on the curve the tissue happens to be operating, which is why position has to be stated before the magnitude is discussed.

Study strategy

Exam move

Draw both curves on one set of axes and mark the lung and tissue pressures, then read off and subtract the saturations rather than quoting them. Repeat with the curve shifted to the right and note how much more the difference grows. Finally, connect the chapter forwards: write one sentence on what happens to the carriers of the previous chapter when oxygen is unavailable.

Working through Cellular Oxygenation in LSM2106? Sia is AskSia’s AI Biology tutor — ask any LSM2106 Cellular Oxygenation question and get a clear, step-by-step explanation grounded in how LSM2106 is taught and assessed. Read this chapter free, then take your hardest questions to Sia.

A+Everything unlocked
Unlocks this Bible + all 4 of your National University of Singapore subjects - and 1,000+ Bibles across every Australian university.
Sia - your LSM2106 tutor, unlimited, worked the way the exam marks it
The full 4-page Bible + practice bank with worked solutions
Chrome extension - sync your LMS so Sia knows your deadlines
Bilingual EN / Chinese on every Bible and every Sia answer
$0.99 Trial
30-day money-back · cancel in one tap · how it works