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PHYC10004 Chap.10 Photons: Blackbody, Photoelectric and Compton Effects

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Chapter 10 of 13 · PHYC10004

Photons: Blackbody, Photoelectric and Compton Effects

Week 8 begins the quantum block with the experiments that forced physics to treat light as particles.

Blackbody radiation follows Wien's law for its peak wavelength and the Stefan-Boltzmann law for its total power, but classical theory predicted an ultraviolet catastrophe; Planck resolved it by quantising energy in steps of hf.

Einstein's photon explains the photoelectric effect: one photon of energy hf ejects one electron, whose maximum kinetic energy is hf − φ, so a threshold frequency exists and brighter light raises the current without changing the stopping voltage.

The laboratory measures Planck's constant from exactly this relation. X-ray tubes produce a continuous spectrum with a sharp short-wavelength cutoff plus characteristic lines, and Compton scattering shows that photons carry momentum p = h/λ: scattered X-rays emerge with longer wavelength by an amount that depends only on the scattering angle.

The chapter works in electronvolts with hc ≈ 1240 eV nm, and switches to joules for photon counts.

In this chapter

What this chapter covers

  • 01

    Blackbody Radiation

  • 02

    Wien and Stefan-Boltzmann Laws

  • 03

    The Ultraviolet Catastrophe

  • 04

    Photon Energy and Momentum

  • 05

    The Photoelectric Effect

  • 06

    Work Function and Stopping Voltage

  • 07

    X-ray Production

  • 08

    Compton Scattering

  • 09

    Photon Counting

Worked example · free

Count the photons leaving a laser pointer

Q [3 marks]. A 5.0 mW laser pointer emits light of wavelength 650 nm. Find the energy of each photon and the number of photons it emits per second. The weighting is an AskSia practice allocation only and does not come from any University marking scheme.
Blackbody spectra at 3000, 4500 and 6000 kelvin from Planck's formula: each curve rises to a peak and falls away, and the peak moves to shorter wavelength and gBlackbody spectra at 3000, 4500 and 6000 kelvin from Planck's formula: each curve rises to a peak and falls away, and the peak moves to shorter wavelength and grows sharply taller as the temperature increases.λ (μm)u(λ) scaled6000 K4500 K3000 K0.511.522.5
Blackbody spectra at 3000, 4500 and 6000 kelvin from Planck's formula: each curve rises to a peak and falls away, and the peak moves to shorter wavelength and grows sharply taller as the temperature increases.
  • 1Photon energy: E = hc/λ = 1240 eV nm/650 nm = 1.91 eV.
  • 1Convert to joules for use with a power: 1.91 × 1.6022 × 10⁻¹⁹ = 3.06 × 10⁻¹⁹ J.
  • 1Photon rate: n = P/E = 5.0 × 10⁻³/3.06 × 10⁻¹⁹ = 1.6 × 10¹⁶ photons per second.
Each photon carries 1.91 eV, and about 1.6 × 10¹⁶ photons leave per second.
Sia tip — Divide a power in watts only by a photon energy in joules; an energy left in electronvolts gives a rate wrong by a factor of 1.6 × 10⁻¹⁹.
Glossary

Key terms

Blackbody
A blackbody is an ideal absorber and emitter whose radiated spectrum depends only on its temperature.
Wien's Law
Wien's law states that a blackbody's peak wavelength is inversely proportional to its temperature, λ_max T = 2898 μm K.
Photon
A photon is a quantum of electromagnetic radiation with energy E = hf and momentum p = h/λ.
Work Function
The work function is the minimum energy needed to free an electron from a metal surface, typically a few electronvolts.
Stopping Voltage
The stopping voltage is the reverse voltage that just halts the most energetic photoelectrons, so that eV_stop equals their maximum kinetic energy.
Compton Shift
The Compton shift is the increase in wavelength of a photon scattered by an electron, Δλ = (h/mc)(1 − cos θ).
FAQ

Photons: Blackbody, Photoelectric and Compton Effects FAQ

Why does brighter light not give photoelectrons more energy?

Each electron absorbs a single photon, and a photon's energy depends only on the light's frequency. Brighter light delivers more photons per second, so more electrons are ejected and the current rises, but each electron's maximum kinetic energy and the stopping voltage stay the same.

What does the ultraviolet catastrophe refer to?

Classical theory predicted that a blackbody should radiate ever more energy at shorter wavelengths, without limit. Measured spectra instead peak and fall away. Planck removed the contradiction by assuming energy is exchanged only in steps of hf, the first quantum idea.

Do I need to derive the Compton equation?

The lectures say students are not expected to derive it from first principles. You should be able to use it, explain that the photon gives some energy and momentum to a recoiling electron and so leaves with a longer wavelength, and note that the shift depends only on the angle.

Why is no Compton shift noticed for visible light?

The shift is at most a few picometres, set by h/mc for the electron. For X-rays of tens of picometres that is a large fraction, but for visible light of hundreds of nanometres it is far too small a fraction to notice.

Study strategy

Exam move

Build a single energy ledger for this chapter: compute photon energies in electronvolts with hc ≈ 1240 eV nm and convert to joules only for power and photon counts. Practise the blackbody chain of Wien, Stefan-Boltzmann and photon rate on a star, a planet and a room-temperature object.

Rehearse the photoelectric observations against the classical predictions in a table, then work threshold, stopping-voltage and intensity questions. Finish with Compton chains from incident energy through shift and scattered energy to electron kinetic energy.

Working through Photons: Blackbody, Photoelectric and Compton Effects in PHYC10004? Sia is AskSia’s AI Physics tutor — ask any PHYC10004 Photons: Blackbody, Photoelectric and Compton Effects question and get a clear, step-by-step explanation grounded in how PHYC10004 is taught and assessed. Read this chapter free, then take your hardest questions to Sia.

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