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MATS3004 · Polymer Science and Engineering 1

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Chapter 12 of 12 · MATS3004

Mechanical Properties and Polymer Processing

Weeks 8-10 close the loop from structure to use: the mechanical response (stress-strain curve, modulus, yield stress, tensile strength, toughness, and the effect of temperature and strain rate), then how polymers are shaped in Processing I and II. The chapter connects microstructure (crystallinity, molecular weight, crosslinking) to the property targets a processing route must hit, and its calculations — Young's modulus from a stress-strain curve and the melt-viscosity scaling with molecular weight — are exam staples.

In this chapter

What this chapter covers

  • 01Stress-strain curve: Young's modulus E = σ/ε (initial slope), yield stress, ultimate tensile strength, elongation at break, toughness = area under the curve
  • 02Effect of temperature and strain rate: polymers are stiffer and more brittle cold or fast, softer and more ductile hot or slow
  • 03Viscoelasticity: creep (strain grows at constant stress), stress relaxation (stress decays at constant strain)
  • 04Mechanical classes: fibre (high modulus, low elongation), plastic (yields then draws), elastomer (low modulus, high recoverable strain)
  • 05Melt rheology: polymer melts are shear-thinning (pseudoplastic), power law τ = K(dγ/dt)ⁿ with n < 1
  • 06Zero-shear melt viscosity vs molecular weight: η₀ ∝ M below the entanglement molar mass Me, η₀ ∝ M^3.4 above Me
  • 07Processing I: extrusion (continuous profiles, film, pipe) and injection moulding (discrete parts)
  • 08Processing II: blow moulding, calendering, thermoforming, fibre spinning; thermosets shaped before an irreversible cure
Worked example · free

Young's modulus from a stress-strain curve and the molecular-weight lever on melt viscosity

Q [4 marks]. (a) In a tensile test on a thermoplastic, the initial linear region reaches a stress of 20 MPa at a strain of 0.005. Find the Young's modulus E. (b) The same polymer is processed above its entanglement molar mass, where the zero-shear melt viscosity scales as η₀ ∝ M^3.4. If the grade's molecular weight is doubled, by what factor does η₀ increase? (4 marks)
  • +1(a) Young's modulus is the initial slope of the stress-strain curve, E = σ/ε, valid in the linear (elastic) region.
  • +1(a) Substitute: E = 20 MPa / 0.005 = 4000 MPa = 4.0 GPa — a typical glassy-thermoplastic stiffness.
  • +1(b) Above the entanglement molar mass the scaling is η₀ ∝ M^3.4, so doubling M multiplies the viscosity by the factor 2^3.4.
  • +1(b) Evaluate 2^3.4 = 2³ × 2^0.4 = 8 × 1.32 ≈ 10.6. So the melt viscosity rises about 10.6-fold when the molecular weight doubles.
(a) E = σ/ε = 20/0.005 = 4000 MPa = 4.0 GPa. (b) η₀ increases by 2^3.4 ≈ 10.6 times. The strong 3.4-power dependence is why molecular weight is a double-edged lever: raising it improves mechanical properties (toughness, entanglement) but makes the melt far harder to push through a die or into a mould, so processing grades trade the two off.
Sia tip — Take Young's modulus only from the initial straight portion of the curve — using a point past the yield stress underestimates E badly. For the viscosity scaling, remember the exponent switches: η₀ ∝ M below the entanglement molar mass Me but η₀ ∝ M^3.4 above it, so always check whether the grade is entangled before applying the 3.4 power.
Glossary

Key terms

Young's modulus (E)
The stiffness of a material, E = σ/ε, taken as the initial slope of the stress-strain curve in the linear elastic region. Fibres have the highest E, elastomers the lowest.
Yield stress
The stress at which a plastic stops deforming elastically and begins to deform permanently (the onset of drawing/necking). Beyond it the material may cold-draw before reaching its ultimate tensile strength.
Toughness
The energy absorbed per unit volume before fracture, equal to the area under the stress-strain curve. A tough polymer combines reasonable strength with substantial elongation, unlike a strong-but-brittle fibre.
Viscoelasticity
The combination of elastic (spring-like) and viscous (flow-like) response that makes polymer properties depend on time and temperature. It shows as creep (strain increasing under constant stress) and stress relaxation (stress decaying at constant strain).
Shear thinning (pseudoplastic)
The fall in melt viscosity as shear rate rises, described by the power law τ = K(dγ/dt)ⁿ with n < 1. It is what lets highly viscous polymer melts be pumped quickly through dies and gates during processing.
Entanglement molar mass (Me)
The molar mass above which chains entangle enough to dominate melt flow and mechanical response. Below Me the zero-shear viscosity scales as η₀ ∝ M; above Me it scales much more steeply as η₀ ∝ M^3.4.
FAQ

Mechanical Properties and Polymer Processing FAQ

How do I read Young's modulus, yield and toughness off a stress-strain curve?

Young's modulus is the slope of the initial straight-line portion, E = σ/ε — measure it only in that elastic region, before any curvature. The yield stress is the stress where the curve bends over and permanent deformation begins (often a peak before necking). The ultimate tensile strength is the highest stress reached, and the elongation at break is the strain at the point of fracture. Toughness is the whole area under the curve up to fracture, so a material can be strong but brittle (small area) or weaker but very tough (large area).

Why does molecular weight have such a strong effect on melt viscosity?

Because above the entanglement molar mass Me the chains thread through one another, and longer chains are entangled at many more points, so moving them past each other becomes disproportionately harder. The result is the steep scaling η₀ ∝ M^3.4 — doubling the molecular weight raises the melt viscosity roughly tenfold. Below Me, where chains are too short to entangle, the dependence is only linear (η₀ ∝ M). This is a central processing trade-off: high molecular weight gives better solid-state properties but a much stiffer, harder-to-process melt.

How does microstructure decide which processing route to use?

Because processing must respect whether the polymer can be remelted and how it flows. Thermoplastics soften on heating, so they suit extrusion (continuous profiles, film, pipe), injection moulding (discrete parts), blow moulding and fibre spinning, and can be reprocessed. Thermosets must be shaped before their irreversible cure — compression or transfer moulding — because once crosslinked they cannot be remelted. Molecular weight, crystallinity and crosslinking set the melt viscosity, the melting or softening temperature and the achievable properties, so they dictate both the route and the conditions.

How is this examined in MATS3004?

As stress-strain interpretation and calculation (Young's modulus, identifying yield/UTS/toughness, comparing fibre/plastic/elastomer curves), the effect of temperature and strain rate, and melt-flow reasoning including the η₀ versus molecular weight scaling and the structure-to-processing link. It is the integrating chapter, so questions often connect microstructure to a property or processing choice. Confirm the assessed scope on the UNSW course outline / Moodle.

Study strategy

Exam move

Practise pulling every quantity off a stress-strain curve — modulus from the initial slope, yield stress, ultimate tensile strength, elongation at break, toughness as the area — and be able to sketch and contrast the fibre, plastic and elastomer curves from memory. Learn the melt-flow facts that carry marks: melts are shear-thinning (τ = K(dγ/dt)ⁿ, n < 1) and η₀ switches from ∝ M to ∝ M^3.4 at the entanglement molar mass, so molecular weight trades solid-state properties against processability. Keep the structure-to-processing links explicit (thermoplastic vs thermoset routes; how crystallinity and crosslinking constrain shaping). Because this chapter integrates the whole course, use it to tie synthesis, characterization and properties together for the Final. Confirm the examinable processing routes on the UNSW course outline / Moodle.

Working through Mechanical Properties and Polymer Processing in MATS3004? Sia is AskSia’s AI Engineering tutor — ask any MATS3004 Mechanical Properties and Polymer Processing question and get a clear, step-by-step explanation grounded in how MATS3004 is taught and assessed. Read this chapter free, then take your hardest questions to Sia.

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