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AMME1362 Chap.6 Crack Growth and Fracture Toughness

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Chapter 6 of 13 · AMME1362

Crack Growth and Fracture Toughness

Fracture mechanics combines nominal stress, flaw size and geometry into a crack-tip stress intensity. A crack becomes critical when the driving intensity reaches the material resistance under the relevant constraint. The method explains why a component can fail below a smooth-specimen strength. Valid application requires a compatible geometry factor, crack definition, toughness condition, section thickness and environment.

In this chapter

What this chapter covers

  • 01

    Stress concentration and sharp cracks

  • 02

    Mode I stress intensity

  • 03

    Geometry factors

  • 04

    Critical crack size

  • 05

    Fracture toughness

  • 06

    Constraint and brittle transitions

Worked example · free

Find a critical crack size

Q [4 marks]. Take toughness as 30 MPa√m, applied stress as 150 MPa and geometry factor as 1.0. Using K = Yσ√(πa), find critical a. Marks here create an authored reasoning split and are not an official University marking scheme.
Allowable stress falls as flaw size grows because stress intensity scales with stress times the square root of crack size.Allowable stress falls as flaw size grows because stress intensity scales with stress times the square root of crack size. The green region shows combinations that remain below the material fracture-toughness boundary.K = Kc boundarysafe regionflaw size, aallowable stress
Allowable stress falls as flaw size grows because stress intensity scales with stress times the square root of crack size. The green region shows combinations that remain below the material fracture-toughness boundary.
  • 1Rearrange to a equals one over pi times toughness divided by geometry factor and stress, squared.
  • 1Calculate the ratio 30 divided by 150, giving 0.200 square-root metres.
  • 1Square and divide by pi: 0.0400 divided by pi equals 0.0127 m.
  • 1Convert to about 12.7 mm and state that the result depends on the chosen geometry and valid toughness condition.
The critical crack size is approximately 0.0127 m, or 12.7 mm, for the stated ideal geometry.
Sia tip — Do not drop the geometry factor or confuse full crack length with the a used by the selected expression.
Glossary

Key terms

Stress intensity
A crack-tip driving parameter combining stress, crack size and geometry.
Geometry factor
A dimensionless correction for crack and component geometry.
Critical crack
A flaw size at which the applied crack driving force reaches resistance.
Plane strain
A highly constrained crack-tip condition approached in sufficiently thick specimens.
Crack driving force
The mechanical intensity promoting crack extension under a stated load and geometry. In a simple Mode I treatment it rises with nominal stress, square-root crack size and the geometry factor, and is compared with material resistance.
Detection limit
The smallest flaw an inspection method can reliably identify in the relevant location and orientation. Damage-tolerant planning places this limit below an allowable flaw size with margin and accounts for growth before the next inspection.
Plastic zone
A region of irreversible deformation around a crack tip that blunts the ideal elastic singularity. Its size depends on stress and yield resistance, while surrounding thickness and constraint affect whether a transferable plane-strain condition is achieved.
FAQ

Crack Growth and Fracture Toughness FAQ

Why can a crack cause failure below yield strength?

A sharp crack concentrates the local field and creates a high crack-tip driving intensity even when nominal stress is modest. The remaining ligament and geometry govern whether crack growth becomes unstable.

Is toughness the same as fracture toughness?

No. Tensile toughness is area under a stress-strain curve per volume. Fracture toughness is a crack-growth resistance parameter measured under specified crack geometry and constraint conditions.

Why does thickness matter in fracture testing?

Thicker sections restrict out-of-plane deformation and promote plane-strain constraint. Thin specimens can develop larger plastic zones and yield a resistance value that is not transferable as a valid plane-strain toughness.

Study strategy

Exam move

Use a fixed setup sequence for every fracture problem. Draw the component boundary and crack, label the crack dimension used by the chosen expression, show nominal loading and write the geometry factor symbolically. Only then copy values. This prevents a full crack length from being substituted where the model uses a half-length and keeps an edge-crack factor from disappearing.

Recalculate the core relation in three directions: solve for stress, solve for crack size and solve for required toughness. Perform a dimensional check each time so stress multiplied by square-root length matches toughness units. Convert millimetres to metres before the square root, not after it. For each result, rebuild the original expression to verify that the calculated critical condition returns the stated resistance.

Draw a driving-force diagram with applied stress intensity rising as crack size grows and a horizontal resistance level for a simple brittle case. Mark stable operation, critical equality and unstable growth. Then change nominal stress and geometry factor separately to see how the critical size moves. This makes inspection limits and stress reduction visible as different interventions on the same inequality.

Prepare a validity checklist for fracture-toughness data: crack sharpness, loading mode, specimen geometry, thickness or constraint, temperature, loading rate and environment. Explain why a thick plane-strain value cannot be replaced casually by a thin-specimen result with more crack-tip plasticity.

Add a low-temperature or high-rate scenario and predict how a ductile-to-brittle tendency could alter resistance without changing nominal alloy name. Practise reading fracture surfaces as a history. Identify an origin, progressive region and final rapid region, but keep fatigue markings separate from single-event brittle features. Pair macroscopic location with microscopy only when scale is stated.

If several origins are possible, propose the section or imaging view that would distinguish them. Build three prevention answers from the two sides of the fracture condition. Removing or blunting a flaw reduces the driving term; lowering stress reduces the same term; selecting a tougher condition raises resistance. Increasing thickness may instead raise constraint and is not automatically protective.

Attach a verification method to each recommendation. Finish with damage-tolerance reasoning. Given an inspection detection limit, compare it with a calculated critical size and require a safety margin rather than equality. Name the assumed growth between inspections and the consequence of missed surface or embedded flaws. End each practice response with one sentence on model boundaries.

That sentence should state geometry, constraint or environment, not a vague warning that real life differs.

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