UNSW Sydney · FACULTY OF CHEMISTRY

DPST1031 Chap.10 Heat, Enthalpy and Hess's Law

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Chapter 10 of 13 · DPST1031

Heat, Enthalpy and Hess's Law

Thermochemistry measures the energy that chemical change exchanges with its surroundings. This chapter defines system, surroundings and the open, closed and isolated cases, applies the first law as ΔU = q + w with the system's sign convention, and turns calorimeter temperature changes into heat using specific, molar and calorimeter heat capacities.

It distinguishes internal energy from enthalpy, links them through the moles of gas in a reaction, and lists the named standard enthalpy changes. Hess's law, formation enthalpies, bond enthalpies and the Born-Haber cycle then let you calculate enthalpy changes that cannot be measured directly, which the Mastery questions on this topic rely on.

In this chapter

What this chapter covers

  • 01

    System, surroundings and universe

  • 02

    The first law and the sign of q and w

  • 03

    Heat capacity and calorimetry

  • 04

    Constant-volume and constant-pressure heat

  • 05

    Enthalpy versus internal energy

  • 06

    Standard enthalpy changes and standard states

  • 07

    Hess's law and enthalpy cycles

  • 08

    Formation enthalpies, bond enthalpies and Born-Haber

Worked example · free

Enthalpy of forming carbon monoxide by Hess's law

Q [4 marks]. Burning carbon to CO₂ has ΔH° = −393.5 kJ and burning CO to CO₂ has ΔH° = −283.0 kJ. Find ΔH° for C(s) + ½O₂(g) → CO(g). The marks are an AskSia practice weighting, not a University allocation.
Enthalpy levels drawn to scale for burning carbon: the direct route to CO₂ releases 393.5 kJ, and the two-step route through carbon monoxide releases 110.5 kJ tEnthalpy levels drawn to scale for burning carbon: the direct route to CO₂ releases 393.5 kJ, and the two-step route through carbon monoxide releases 110.5 kJ then 283.0 kJ, the same total, because enthalpy is a state function.C(s) + O₂(g)CO(g) + ½O₂(g)CO₂(g)−393.5 kJ−110.5 kJ−283.0 kJenthalpy
Enthalpy levels drawn to scale for burning carbon: the direct route to CO₂ releases 393.5 kJ, and the two-step route through carbon monoxide releases 110.5 kJ then 283.0 kJ, the same total, because enthalpy is a state function.
  • +1Keep C(s) + O₂(g) → CO₂(g), ΔH° = −393.5 kJ.
  • +1Reverse CO(g) + ½O₂(g) → CO₂(g): CO₂(g) → CO(g) + ½O₂(g), ΔH° = +283.0 kJ.
  • +1Add the two equations: CO₂ and ½O₂ cancel, leaving C(s) + ½O₂(g) → CO(g).
  • +1ΔH° = −393.5 + 283.0 = −110.5 kJ.
Forming CO from carbon releases 110.5 kJ per mole, a value that cannot be measured directly but follows from two measurable combustions.
Sia tip — When you reverse a step, change the sign of its ΔH before adding; most Hess's law errors are a sign left unchanged.
Glossary

Key terms

State function
A property, such as U or H, whose change depends only on the initial and final states.
Internal energy
The total kinetic and potential energy of the particles in a system.
Heat capacity
The heat needed to raise the temperature of an object or sample by one kelvin.
Enthalpy
The state function H whose change equals the heat exchanged at constant pressure.
Exothermic reaction
A reaction that releases heat to the surroundings, with a negative ΔH.
Hess's law
The rule that a reaction's enthalpy change is the same for every route between the same states.
Lattice enthalpy
The enthalpy change when one mole of an ionic solid forms from its gaseous ions.
FAQ

Heat, Enthalpy and Hess's Law FAQ

What sign convention does the course use for work?

Signs are taken from the system's point of view. Heat absorbed by the system and work done on the system are positive; heat released and work done by the system are negative. With that convention the first law is written ΔU = q + w.

When are ΔU and ΔH different?

They differ by the expansion or compression work of gases, ΔH = ΔU + Δn(gas)RT. If a reaction does not change the number of moles of gas, the two are almost equal. A bomb calorimeter measures ΔU, while a constant-pressure calorimeter measures ΔH.

Why is the formation enthalpy of an element zero?

Formation enthalpy is defined as the change when a compound forms from its elements in their standard states. An element already in its standard state needs no change to form itself, so its value is zero by definition. A different form, such as diamond rather than graphite, is not zero.

Why use a Born-Haber cycle?

The lattice enthalpy of an ionic solid cannot be measured directly. The Born-Haber cycle links it, through Hess's law, to quantities that can be measured: sublimation, bond, ionisation and electron affinity energies and the enthalpy of formation, so the unknown can be calculated.

What is the difference between heat and temperature?

Temperature measures the average kinetic energy of the particles and is read with a thermometer. Heat is energy transferred because of a temperature difference. The same heat raises the temperature of a small sample more than a large one, which is why calorimetry needs a heat capacity to connect the two.

Study strategy

Exam move

Learn the sign convention by working three first-law problems in which heat and work have different signs. Next practise calorimetry in both forms, a bomb calorimeter with a heat capacity and a solution with mcΔT, and always state whether the result is ΔU or ΔH. Then work Hess's law problems in three styles: combining given equations, using formation enthalpy tables, and building a Born-Haber cycle.

For each, write the target equation first and sketch the cycle or level diagram before calculating. Finish by converting between ΔU and ΔH for reactions with and without a change in gas moles.

Working through Heat, Enthalpy and Hess's Law in DPST1031? Sia is AskSia’s AI Chemistry tutor — ask any DPST1031 Heat, Enthalpy and Hess's Law question and get a clear, step-by-step explanation grounded in how DPST1031 is taught and assessed. Read this chapter free, then take your hardest questions to Sia.

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